Synthesis of Benzanilide and Methyl 3-Nitrobenzoate and the Identification of ‘Unknowns’ from Spectroscopic and Physical Properties
James Lucas
10394308
23/11/12
Introduction
In this series of practicals it was the aim to synthesise both Benzanilide and Methyl 3-Nitrobenzoate. Benzanilide was synthesised using The Schotten Baumann reaction which takes a hydrogen atom from an amino group and substitutes it for an acyl group. For Methyl 3-Nitrobenzoate, NO2+ was used as an electrophilic reagent to replace an aromatic hydrogen atom.
Then both chemicals were purified by first determining appropriate recrystallisation solvent, before analysing Benzanilide and Methyl 3-Nitrobenzoate as well as 2 …show more content…
unknown compounds (B & E) using melting point determination and IR spectrometry to find the purity.
Procedure
For method used please refer to CHM1002 Stage 1 Organic Chemistry Practicals Term 1 lab script. Only deviation was that, the use of Decolourising Carbon and Filtration of the hot solution was skipped in this set of practicals
Results
Determination of an appropriate Recrystallisation Solvent
0.02g of crude solid in each test tube. 0.5 cm3 (initially) of solvent in each test tube
Solute: Benzanilide
Solute: Methyl 3-Nitrobenzoate
Solvent
Soluble at 0.5cm3
Soluble at 1.0cm3
Soluble when heated
Recryst-allised
Solvent
Soluble at 0.5 cm3
Soluble at 1.0 cm3
Soluble when heated
Recryst-allised
Methanol
Negative
Negative
Negative
Negative
Methanol
Negative
Negative
Negative
Negative
Ethanol
Negative
Negative
Positive
Positive
Ethanol
Negative
Negative
Negative
Negative
Toluene
Negative
Negative
Positive
Positive
Toluene
Negative
Negative
Negative
Negative
Petroleum Ether
Negative
Negative
Negative
Negative
Petroleum Ether
Negative
Negative
Positive
Positive
Water
Negative
Negative
Negative
Negative
Water
Negative
Negative
Negative
Negative
Solvent used = Ethanol because from Solvent used = Petroleum Ether
COSHH assessment it is shown as being safer than Toluene
After dissolving the product – left to stand for 10-15mins
Melting Points
Compound
Melting Point oC Rough
Melting Point oC #1
Melting Point oC #2
Melting Point oC #3
B
79
79.4
79.3
79.6
E
107
106.8
107.1
107.2
Benzanilide
162
161.7
162.2
163.4
Methyl 3-Nitrobenzoate
77
77.6
77.3
76.8
Selective Reduction Reactions
Compound
Nitro group test
Aromatic amine
Carbonyl Group
Alcoholic Hydroxide
B
Positive
Negative
Positive
Negative
Positive
E
Negative
Positive
Positive
Negative
Negative
Benzanilide
Negative
Positive
Positive
Negative
Negative
Methyl 3-Nitrobenzoate
Positive
Negative
Positive
Negative
Negative
Compound B contains: Nitro group, carbonyl group
Therefore must be either 1-(3-nitrophenyl) ethanoate or 1-(4-nitrophenyl) ethanoate
Compound E contains: Aromatic Amine group, carbonyl group
Therefore must be either 1-(3-aminophenyl) ethanoate or 1-(4-aminophenyl) ethanoate
IR Spectra
Figures 1,2,3,4 – IR Spectrums Relating to Sample B (1), Sample E(2), Methyl 3-Nitrobenzoate(3) and Benzanilide(4)
Discussion
Compound
Literature Melting Points oC
1
78
2
57.59
3
98
4
79
5
N/A
6
107
By looking at the melting points for B & E and comparing them to the literature values, it is possible to narrow the structure of both unknown compounds down from the suggest compounds in the results section (1-(3-nitrophenyl)ethanoate) or 1-(4-nitrophenyl)ethanoate) for compound B and (1-(3-aminophenyl)ethanoate or 1-(4-aminophenyl)ethanoate) for compound E.
Compound
Mean Melting Point oC
B
79.4
E
107.0
From comparison of the two data tables it can seen that Compound E has the same melting point as compound 6, which is 1-(4-aminophenyl)ethanoate.
However for compound B the mean melting point is close to both Compound 1 and Compound 4 so IR spectra are needed to correctly determine the structure of B.
By comparing the IR spectrum for Compound B it can see that it is 1-(4nitrophenyl)ethanoate, this is indicated by the peak at 763.16cm-1 when compared against literature values for IR Spectroscopy shows a C-H bend in the ortho position of the phenyl ring, which points to the position of ethanoate being on the 4th carbon.
Looking back at the yields it can be see that there has been an error in the drying process for Benzanilide resulting in a very high yield of 206%. However this is most likely to only affect the yield result, and not the chemical structure of the synthesis.
Conclusion
Judging by the results from the IR spectra, Melting point determination and chemical tests, It can be assumed that Benzanilide and Methyl 3-Nitro benzoate were both successfully synthesised.
Unknown compound E was identified as compound 6, 1-(4-Aminophenyl) ethanoate. Unknown compound B was identified as compound 4, 1- (4-Nitrophenyl)
ethanoate.
References
First Year Spectra Collection 2012, University of Plymouth
CHM1002 Stage 1 Organic Chemistry Practicals Term 1 Lab Script 2012, University of Plymouth
Clayden, J., Greeves, N., Warren, S. and Wothers, P. (2001) Organic Chemistry, Oxford University Press.
http://www.chemistry.ccsu.edu/glagovich/teaching/316/ir/table.html (accessed 18/11/12