Case Study: Joy The Christmas Island Crab
Arthropod Genetics Passing of Traits
One bright and sunny Australian afternoon, Joy the Christmas Island Crab met her dream crab, a ten-legged green caped crab. They fell in love and had a beautiful crab wedding.
The Generation one crustacean body’s phenotype was a plastic cup while the genotype was BB. The legs’ phenotypes were pearly white pipe cleaners and the genotype was ff. The crustacean had deep blue pom poms for eyes and the genotype was Ii. For antennae, the crustacean had soft qtips and the genotypes were Kk. One of Joy’s structural adaptations were vibrant purple stripes to help the crab camouflage in the colorful rainforest. She also had sharp teeth to scare off predators. Her husband was a heterozygous plastic cup whose genotype was Bb. His legs were colorful straws with the genotype EE. His eyes were colorful pompoms with the genotype ii. He had Ll paperclips for the antenna. His structural adaptation was a green plastic cup with the genotype of SS. …show more content…
Soon, they discovered that Joy was going to have a baby.
The lobster doctors wanted to find the probability of the phenotypes of the baby. So, they made Punnett squares.
The offspring would still have a plastic cup body because both her parent have the dominant gene for a plastic cup. The baby crab would have colored straws and white pipe cleaners for legs because its parents both have dominant genes for the trait. This means that there is incomplete dominance when two dominant traits are shown. The baby could have colorful pompom eyes or blue pompom eyes because both parents have the recessive trait for eyes, and would have a mix of Q-tips and paper clips for antennae because there is incomplete dominance. The baby would have all of the structural adaptations of its parents.
One bright and sunny afternoon in New Jersey, Joy II the Christmas Island crab, met the crab of her dreams, a red spotted red-legged crab. It was love at first sight, and they had a beautiful crab
wedding.
Joy II has a plastic cup body with the genotype BB. She has colored straws and white pipe cleaners for legs because with the genotype Ee. This means that there is incomplete dominance when two dominant traits are shown. She also had colorful pompom eyes, ii, and has a mix of Q-tips and paper clips for antennae because there is incomplete dominance, with the genotype Tt. Her structural adaptations are purple stripes, OO, two sharp teeth, PP, and a green plastic cape, SS. The husband’s Body is styrofoam ball, aa. He has colorful pipe cleaners as legs, Ff. He also has colored buttons, gg, as eyes. His antennae are colored twist ties, jj. His structural adaptation are red paper dots, Rr.
Soon, they discover that Joy II is going to have a baby. The lobster doctors want to find the probability of the phenotypes of the baby crab. So, they make Punnett squares.
The baby crab’s body would be a plastic cup because there is a dominant homozygous trait in her mom, and she would have the phenotype Bb. Her eyes could be either colored pom poms, colored buttons, or both because of incomplete dominance. The phenotype for this would be ig. Her legs would be colored pipe cleaners, and there was a 25% chance of that. The phenotype is Ef. Her antennae are Q-tips and paperclips because of incomplete dominance, so the phenotype is TJ.
When the baby crab was born, she was named Joy III.
One bright and sunny Australian afternoon, Joy the Christmas Island Crab met her dream crab, a ten-legged green caped crab. They fell in love and had a beautiful crab wedding.
The Generation one crustacean body’s phenotype was a plastic cup while the genotype was BB. The legs’ phenotypes were pearly white pipe cleaners and the genotype was ff. The crustacean had deep blue pom poms for eyes and the genotype was Ii. For antennae, the crustacean had soft qtips and the genotypes were Kk. One of Joy’s structural adaptations were vibrant purple stripes to help the crab camouflage in the colorful rainforest. She also had sharp teeth to scare off predators. Her husband was a heterozygous plastic cup whose genotype was Bb. His legs were colorful straws with the genotype EE. His eyes were colorful pompoms with the genotype ii. He had Ll paperclips for the antenna. His structural adaptation was a green plastic cup with the genotype of SS. …show more content…
Soon, they discovered that Joy was going to have a baby.
The lobster doctors wanted to find the probability of the phenotypes of the baby. So, they made Punnett squares.
The offspring would still have a plastic cup body because both her parent have the dominant gene for a plastic cup. The baby crab would have colored straws and white pipe cleaners for legs because its parents both have dominant genes for the trait. This means that there is incomplete dominance when two dominant traits are shown. The baby could have colorful pompom eyes or blue pompom eyes because both parents have the recessive trait for eyes, and would have a mix of Q-tips and paper clips for antennae because there is incomplete dominance. The baby would have all of the structural adaptations of its parents.
One bright and sunny afternoon in New Jersey, Joy II the Christmas Island crab, met the crab of her dreams, a red spotted red-legged crab. It was love at first sight, and they had a beautiful crab
wedding.
Joy II has a plastic cup body with the genotype BB. She has colored straws and white pipe cleaners for legs because with the genotype Ee. This means that there is incomplete dominance when two dominant traits are shown. She also had colorful pompom eyes, ii, and has a mix of Q-tips and paper clips for antennae because there is incomplete dominance, with the genotype Tt. Her structural adaptations are purple stripes, OO, two sharp teeth, PP, and a green plastic cape, SS. The husband’s Body is styrofoam ball, aa. He has colorful pipe cleaners as legs, Ff. He also has colored buttons, gg, as eyes. His antennae are colored twist ties, jj. His structural adaptation are red paper dots, Rr.
Soon, they discover that Joy II is going to have a baby. The lobster doctors want to find the probability of the phenotypes of the baby crab. So, they make Punnett squares.
The baby crab’s body would be a plastic cup because there is a dominant homozygous trait in her mom, and she would have the phenotype Bb. Her eyes could be either colored pom poms, colored buttons, or both because of incomplete dominance. The phenotype for this would be ig. Her legs would be colored pipe cleaners, and there was a 25% chance of that. The phenotype is Ef. Her antennae are Q-tips and paperclips because of incomplete dominance, so the phenotype is TJ.
When the baby crab was born, she was named Joy III.