Compositions and Inverses 
Running Header: INVERSE 1
Composition and Inverse
Esther Bakeberg
MAT222: Week 5 Assignment
Donna Wall
July 21, 2014
INVERSE 2
Composition and Inverse
Functions give us an opportunity for using expressions with different values. The
values can help business owners, (small or large), data collectors and analysts, and even the
consumer compare rates and data. Functions also extend independent (x) and dependent
(y) variables by graphing in the coordinate plane and creating a visual demonstration of
the relationship.
The functions I will be using in the required problems are
f(x) = 5x – 3 g(x) = x2 +2 h(x) = 3 +x / 7
The first task is to compute (f – h) (4).
(f – h) (4) = f(4) – (h - 4) The rules of composition allow each function to be
calculated separately and then subtracted.
f(4) = 5(4) – 3 The x was replaced with the 4 from the problem.
f(4) = 20 – 3 The order of operations is used to evaluate the function.
f(4) = 17 h(4) = (3 +7)/7 Here, the same process was used for h(4) and f(4).
h(4) – 7/7
h(4) = 1
(f - h)(4) = 17 -1
(f – h)(4) = 16 Resulting solution after substituting the values and
subtracting. Two pairs of the functions will be composed into each other next. One way to
find the solution for the function g(x) is to calculate it and then substitute for the x value in the
f(x). The option would
Composition and Inverse
Esther Bakeberg
MAT222: Week 5 Assignment
Donna Wall
July 21, 2014
INVERSE 2
Composition and Inverse
Functions give us an opportunity for using expressions with different values. The
values can help business owners, (small or large), data collectors and analysts, and even the
consumer compare rates and data. Functions also extend independent (x) and dependent
(y) variables by graphing in the coordinate plane and creating a visual demonstration of
the relationship.
The functions I will be using in the required problems are
f(x) = 5x – 3 g(x) = x2 +2 h(x) = 3 +x / 7
The first task is to compute (f – h) (4).
(f – h) (4) = f(4) – (h - 4) The rules of composition allow each function to be
calculated separately and then subtracted.
f(4) = 5(4) – 3 The x was replaced with the 4 from the problem.
f(4) = 20 – 3 The order of operations is used to evaluate the function.
f(4) = 17 h(4) = (3 +7)/7 Here, the same process was used for h(4) and f(4).
h(4) – 7/7
h(4) = 1
(f - h)(4) = 17 -1
(f – h)(4) = 16 Resulting solution after substituting the values and
subtracting. Two pairs of the functions will be composed into each other next. One way to
find the solution for the function g(x) is to calculate it and then substitute for the x value in the
f(x). The option would