D3 118
ause t poon 1 odu- 12-g rous f the ulate at is
Narayan, Srikanth
MECH 2110 - section 0111
November 11th,Article
20143/6 Problems 169
Chapter
Problem
118
page the
169300-kg
3/118 The motor3, unit
A is used to -elevate
Engineering
Mechanics
(Dynamics)
- 7th cylinder at a constant rate of 2 m/s. If the power meter B registers an electrical input of 2.20 kW, Meriam & Kraige calculate the combined electrical and mechanical efficiency e of the system.
Page 1 of 2
ed.
Problem statement: We are given the masses of two cylinders, one bigger than the other, an velocity for the bigger one (as shown), and a motor which powers the motion of the system as shown. The motion is generated by a given electrical input. We are to utilize the given information to find the combined electrical and mechanical efficiency of this system.
100 kg
300 kg
Objective:
A
B
3/119
A
Find the combined efficiency in this system
2 m/s
Methods and assumptions: Our initial approach to this problem will revolve around finding the power output being generated. In order to do this, we will need to know the power that is moving the 300kg cylinder up at a velocity of
Problem 3/118
2 (m/s). We will define a mechanical system consisting of just that cylinder, with a free body diagram showing its rest weight, the tension
A
1700-kg car starts from at position
A and ac-exerted by the pulley system, and the upward velocity. celerates uniformly up the incline, reaching a
However,
the mathematical representation of this tension will be impacted by two things: 1) the speed 100 km/hthat at position
B. Determine the 100kgof cylinder is, on top of any power being generated by the motor, aiding in the lifting of power required just before the car reaches position the 300kg cylinder; and 2) the two-rope pulley that is holding up the cylinder. Having accounted
B and also the power required when the car is for thisbetween mathematically, have a the tension computed strictly for what the motor is generating
Narayan, Srikanth
MECH 2110 - section 0111
November 11th,Article
20143/6 Problems 169
Chapter
Problem
118
page the
169300-kg
3/118 The motor3, unit
A is used to -elevate
Engineering
Mechanics
(Dynamics)
- 7th cylinder at a constant rate of 2 m/s. If the power meter B registers an electrical input of 2.20 kW, Meriam & Kraige calculate the combined electrical and mechanical efficiency e of the system.
Page 1 of 2
ed.
Problem statement: We are given the masses of two cylinders, one bigger than the other, an velocity for the bigger one (as shown), and a motor which powers the motion of the system as shown. The motion is generated by a given electrical input. We are to utilize the given information to find the combined electrical and mechanical efficiency of this system.
100 kg
300 kg
Objective:
A
B
3/119
A
Find the combined efficiency in this system
2 m/s
Methods and assumptions: Our initial approach to this problem will revolve around finding the power output being generated. In order to do this, we will need to know the power that is moving the 300kg cylinder up at a velocity of
Problem 3/118
2 (m/s). We will define a mechanical system consisting of just that cylinder, with a free body diagram showing its rest weight, the tension
A
1700-kg car starts from at position
A and ac-exerted by the pulley system, and the upward velocity. celerates uniformly up the incline, reaching a
However,
the mathematical representation of this tension will be impacted by two things: 1) the speed 100 km/hthat at position
B. Determine the 100kgof cylinder is, on top of any power being generated by the motor, aiding in the lifting of power required just before the car reaches position the 300kg cylinder; and 2) the two-rope pulley that is holding up the cylinder. Having accounted
B and also the power required when the car is for thisbetween mathematically, have a the tension computed strictly for what the motor is generating