Dna Replication

1.
Sequence A

TCT TCC CTC CTA AAC GTT CAA CCG GTT CTT AAT CCG CCG CCA GGG CCC CGC CCC TCA GAA GTT GGT

Sequence B
TCA GAC GTT TTT GCC CCG TAA CAA CTT GTT ACA ACA TGG TCA TAA ACG TCA GAG ATG GTC AAT CTC TTA ATG ACT

Sequence C
TAC AAA CAT GTA AAC ACA CCC TCA GTG GAC CAA CTC CGC AAC ATA AAC CAA ACA CCG CTC GCG CCG AAA AAG ATA TGG

3.
4.
Sequence A - Middle Sequence
AGA AGG GAG GAU UUG CAA GUU GGC CAA GAA UUA GGC GGC GGU CCC GGG GCG GGG AGU CUU CAA CCA

Sequence B - End Sequence
AGU CUG CAA AAA CGG GGC AUU GUU GAA CAA UGU UGU ACC AGU AUU UGC AGU CUC UAC CAG UUA GAG AAU UAC UGA

Sequence C - Beginning Sequence
AUG UUU GUA CAU UUG UGU GGG AGU CAC CUG GUU GAG GCG UUG UAU UUG GUU UGU GGC GAG CGC GGC UUU UUC UAU ACC

FULL SEQUENCE
AUG UUU GUA CAU UUG UGU GGG AGU CAC CUG GUU GAG GCG UUG UAU UUG GUU UGU GGC GAG CGC GGC UUU UUC UAU ACC AGU CUG CAA AAA CGG GGC AUU GUU GAA CAA UGU UGU ACC AGU AUU UGC AGU CUC UAC CAG UUA GAG AAU UAC UGA AGA AGG GAG GAU UUG CAA GUU GGC CAA GAA UUA GGC GGC GGU CCC GGG GCG GGG AGU CUU CAA CCA

5.
Removed Codons 24-66, including codon 66
AUG UUU GUA CAU UUG UGU GGG AGU CAC CUG GUU GAG GCG UUG UAU UUG GUU UGU GGC GAG CGC GGC UUU GGG GCG GGG AGU CUU CAA CCA

6.
Met phe val asn gln his leu cys gly ser his leu val glu ala leu tyr leu val cys gly gl arg pro phe phe tyr thr pro gly ile val glu gln cys cys thr ser ile cys ser tyr gln leu glu asn tyr cys asn

Analysis a) The beginning fragment was sequence C. I know because the first codon of the sequence is “AUG” and that is the start codon. b) The end fragment was Sequence B. I know because the last codon of the sequence was “UGA” and that is one of the three end codons (UAG, UAA, or