1. Determine the load voltage by deriving an equivalent circuit for the circuit below. Reduce the R1, R2, and R3 combination to a single equivalent resistance. Also, reduce R4 and RL1 to a single resistance.
RA-B:_408Ω____ RC:__99Ω____
VL1:_1.952V______
Ra= R1+R2= 470Ω+220Ω= 690Ω
Rab= Ra//R3= 690Ω(1kΩ)/690Ω+1kΩ= 690000/1690= 408Ω
Rc= R4//RL1= 220Ω(180Ω)/220Ω+180Ω= 39600/400= 99Ω
Rt= Rab//Rc= 408Ω(99Ω)/408Ω+99Ω= 40392/507= 79.66Ω
VL1= V x Rt/Rab= 10V x 79.66Ω/408Ω= 1.952V
2. Download the Multisim file “Ser_Par3” from Doc Sharing, Week 5. Run the simulation and verify the simulated load voltage matches the calculated value.
VL1:_1.952V_____
Did they match (YES/NO)? If no, determine why and correct it. Yes the results matched.
3. Modify the Multisim file to match the equivalent circuit you developed in problem #1 (Battery and two equivalent resistors). Run the simulation and compare the equivalent circuit’s results with the original circuit’s results. Are the results the same (YES/NO)? If no, determine why and correct it
Yes the results are the same.
4. Construct the original circuit above on the breadboard. Connect the circuit’s input to a DC power supply and set it to +10 V. Use a hand held DMM to adjust the supply to +10 V. Using the hand held DMM, measure the load voltage. Have the professor verify the circuit before applying power.
VL1:_1.302V____
Does the value match the calculated and simulated values (YES/NO)? If no, determine why and correct it.
Yes, we you account for the resistors being a little different in measurement the reading is accurate. My resistors weren’t exactly the same value. Instead of 220Ω it was 218Ω. And the other was supposed to be 180Ω but only measured to be 178.5Ω. So that makes the reading a little lower than it should be.
Measuring the voltage across the resistors.
5. If using ELVIS, repeat step 4 using the ELVIS