1) Place a positive 1 nano-coulomb charge on the screen.
2) Turn on “Show numbers”
3) Turn on “tape measure”.
4) Use the tape measure to find and record the distance from the charge to the equipotential sensor.
1.88 m
5) Record the voltage as indicated on the equipotential sensor.
4.1v
6) Change the location of the positive charge to at least six widely different distances from the equipotential sensor. Record the voltag8.3v 2.5m
13.1v 2.19m 3.4v 3.8m 2.8v 2.24m 1.8v 4.5m 2.5v 2.61
7) Use “Excel” to plot these data sets.
8) What is the mathematical relation between these variables?
When voltage increases distance decreases and viceversa.
9) Click on “Clear All” Part 2: What are the characteristics of the electric field sensors?
1) Place a positive 1 nano-coulomb charge at the center of the screen.
2) Click on “Show Numbers.
3) Bring out an electric field senor.
4) What are electric field units?
5.9v/m 47.7 degrees.
5) Is the electric field a scalar or a vector?
Vector because it has a direction.
6) To do its job, the electric field senor should have a charge. Why?
Because in order to show direction it needs to have a charge.
7) Does the field senor have a positive or negative charge.
Positive
8) Turn on the “Tape measure”.
9) As you sample the electric field further and further from a charged object, you find that the field strength weakens. Do you think the E field vs. distance relation is an inverse relation, an inverse square, or some other power relation? Use the electric field sensor and tape measure to collect data sets in order to answer this question. Include the “Excel” graph that you made in order to see if you hypothesis was correct. Were you correct?
It is some other power relation. Because initially distance on tape measure is 2.17m