Preview

Exercise 18 Statistics

Satisfactory Essays
Open Document
Open Document
509 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Exercise 18 Statistics
Sohal, S
04/05/11
(HLT-362 V) Applied Statistics for Healthcare Professionals
Exercise 18

Q1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between ( - 53.68, 64.64),where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places.
Answer: Mean of weight relative to ideal = 5.48 and Standard Deviation (σ) = 22.93. Calculation: (x bar) 1.96(σ)
5.48± 1.96(22.93)
5.48 - 1.96(22.93) = 5.48 - 44.94 = (-39.46)
5.48 + 1.96(22.93) = 5.48 + 44.94 = 50.42
Expressed as (-39.46, 50.42)

Q2. Which of the following values from Table 1 tells us about variability of the scores in a distribution?
a. 60.22
b. 11.94
c. 22.57
d. 53.66
Answer: c

Q3. Assuming hat the distribution for General health Perceptions is normal, 95% of the female’s scores around the mean were between what values? Round your answer to two decimal places.
Answer: x bar = 39.71, σ = 25.46
Calculation: (x bar) 1.96(σ)
39.71 ± 1.96(25.46)
39.71 – 1.96(25.46) = 39.71 – 49.90 = (-10.19)
39.71 + 1.96(25.46) = 39.71+ 49.90 = 89.61
Expressed as (-10.19, 89.61)

Q4. Assuming that the distribution of scores for Pain is normal, 95% of the men's scores around the mean were between what two values? Round your answer to two decimal places.
Answer: (x bar) = 52.53, σ = 30.90
Calculation: (x bar) 1.96(σ)
52.53 ± 1.96(30.90)
52.53 – 1.96(30.90) = 52.53 – 60.56 = (-8.03)
52.53 + 1.96(30.90) = 52.53+ 60.56 = 113.09
Expressed as (-8.03, 113.09)

Q5. Were the body image scores significantly different for women versus men? Provide a rationale for your answer.
Answer: Yes, the body image scores for women were significantly higher (73.07 ± 16.93), then men (60.22 ± 16.98). It indicates a positive correlation between quality of life and improved body image.

Q6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the men's Mental health scores around

You May Also Find These Documents Helpful

  • Satisfactory Essays

    c) Judging from the results we can see that the CEO’s have bigger desks than the governors. The difference between mean and standard deviation is that mean is the sum of the scores divided by the number of scores and standard deviation is the square root of the average of the squared deviations from the mean.…

    • 608 Words
    • 3 Pages
    Satisfactory Essays
  • Powerful Essays

    What is the growth rate of its real GDP? Assume that population is 100 in year 1 and102 in year 2.…

    • 1365 Words
    • 7 Pages
    Powerful Essays
  • Good Essays

    QNT 561 Final Exam

    • 697 Words
    • 5 Pages

    11. We wish to develop a confidence interval for the population mean. The population follows the normal distribution, the standard deviation of the population is 3, and we have a sample of 10 observations. We decide to use the 90 percent level of confidence. The appropriate value of to represent the level of confidence is…

    • 697 Words
    • 5 Pages
    Good Essays
  • Satisfactory Essays

    HLT 362 Exercise 18

    • 352 Words
    • 2 Pages

    Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 352 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Math 116

    • 1192 Words
    • 5 Pages

    The variable X is normally distributed. The mean is μ = 15.2 and the standard deviation is σ = 0.9.…

    • 1192 Words
    • 5 Pages
    Good Essays
  • Good Essays

    Math 107 Quiz

    • 577 Words
    • 3 Pages

    a) Use the histogram to find the probability that a person selected at random from the survey’s sample had a test score of more than two.…

    • 577 Words
    • 3 Pages
    Good Essays
  • Good Essays

    Exer20

    • 494 Words
    • 2 Pages

    Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 494 Words
    • 2 Pages
    Good Essays
  • Powerful Essays

    St 101 Question Paper

    • 2716 Words
    • 11 Pages

    Important Note: While most of the questions on this sample exam are in a multiple choice format, the questions on the exam will for the most part be partial credit type questions where you must show some work to obtain full credit. 1. The heights of American men aged 18 to 24 can be described by a Normal model with mean 68 inches and standard deviation 2.5 inches. Half of all young men are shorter than a) 65.5 inches b) 68 inches c) 70.5 inches d) can't tell because the median height is not given Use the information in Problem 1 and the 68-95-99.7 rule to determine the percentage of young men that are taller than 6' 1". The grade point averages (GPA) of…

    • 2716 Words
    • 11 Pages
    Powerful Essays
  • Satisfactory Essays

    Exercise 20

    • 458 Words
    • 2 Pages

    7. Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 458 Words
    • 2 Pages
    Satisfactory Essays
  • Powerful Essays

    302 Mid Notes

    • 2019 Words
    • 9 Pages

    The worksheet “Insurance” in the Excel workbook MATH302_Midterm.xls, which is attached, contains data on the percentage of people without health insurance coverage. These data are based on samples taken in 2004 for the fifty states and the District of Columbia. Use these data to answer questions 1 and 2.a. On average, what percentage of the people in the fifty states and the District of Columbia do not have health insurance? Mean: 14.15 Round your answer to 2 decimal places as necessary.b. What is the median percentage of people in the fifty states and District of Columbia who do not have health insurance? Median: 13.50 Round your answer to 2 decimal places as necessary.c. What is the standard deviation of the percentage of people in the fifty states and District of Columbia who do not have health insurance?Standard deviation: 4.10 Round your answer to 2 decimal places as necessary. Answer Key: 14.15, 13.50, 3.96|4.16…

    • 2019 Words
    • 9 Pages
    Powerful Essays
  • Satisfactory Essays

    Module 3

    • 250 Words
    • 2 Pages

    7. Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 250 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    #2. A sample was taken of 36 people attending a school with an annual average tuition of $3800 and the population standard deviation of $620. Find the 95% confidence interval of the true mean.…

    • 300 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    Quantitative Techniques

    • 28578 Words
    • 115 Pages

    3. If you are told a population has a mean of 25 and a variance of 0, what must you conclude?…

    • 28578 Words
    • 115 Pages
    Satisfactory Essays
  • Powerful Essays

    |% | | |9 years old and |150 |43.48 | | |below | | | | | | | | | |10 years old |121 |35.07 | | | | | | | | | | | | |11 years old and |74 |21.45 | | |above | | | | | | | | | | TOTAL |345 |100 | | | | | | | Table 2 shows that 150 (43.48) who took the test are 9 years old and below, 121 pupils (35.07) responded to the survey and 74 (21.45) pupils answered the test survey given. | Table 3 | | | Percentage Distribution of Pupil Respondents by | |Sex | | | | | | | | | |Sex |f |% | |Male |175 |50.72 | | | | | | | | | |Female |170 |49.28 | | | | | | TOTAL |345 |100 | | | | | Table 3 shows that 175 (50.72) were male and 170 (49.28) are female who took the reading test study.…

    • 7410 Words
    • 30 Pages
    Powerful Essays
  • Satisfactory Essays

    Statistics Problem Sample

    • 321 Words
    • 2 Pages

    1.The scores of 15 masteral students in Statistics were 80,85,78,90,91,98,95,98,95,74,71,72,98,99,and 87. Find the measures of central tendency, the range, the variance, and the standard deviation.…

    • 321 Words
    • 2 Pages
    Satisfactory Essays