Faculty of Engineering and Technology
Thermodynamics Lab Report
Expirement No.2
Instructor: Eng. Rebhi Al-Mashaleh
Students Names:
Fareed Shatara 2110302 فريد ماهر شطارة
Hanna Mansour 0128358 حنا سليم منصور
Ghassan Hjazi 0127296 غسان حجازي
Ahmad Abu Malloh 0127293 أحمد ابو ملوح
Omar Al Khateeb 0120533 عمر الخطيب
Section: 2
Date: 16 / 03 /2014
Objectives:
To Investigate The Relationship Between The pressure And The Temperature For a Saturated Steam in a Constant Volume Tank. And To verify the Clausius – Claperon Equation.
Apparatus :
Gunt Marcet Boiler
Theory:
= where :
T = Abs. Temp.
Vfg = Vg – Vf
Hfg = hf – hg
Results and Calculations:
Gauge Pressure (bar)
Absoulte Pressure
Steam Temp . Increasing Pressure
Steam Decreasing Pressure
Mean Temp.
0
0.9
95
97.5
96.25
1
1.9
115.2
117.7
116.45
2
2.9
129.5
132
130.75
3
3.9
140
142.5
141.25
4
4.9
148.6
150.3
149.45
5
5.9
156.3
157.5
156.9
6
6.9
161.9
163.9
162.9
7
7.9
168.1
169.5
168.8
8
8.9
172.5
174.7
173.6
9
9.9
177.1
179.6
178.35
10
10.9
182.2
182.2
182.2
Table(1)
Graph & Plotting :
Graph Eqaution :
Using Matlab we Get This Equation y = p1*x^2 + p2*x + p3
Coefficients:
p1 = -6.9843e-05 p2 = 0.16191 p3 = 86.397
Sample Of Calculations :
Theoretical dT/dP : -
The clausius-claperon equation was used for calculating the theoretical dT/dp :
= T . Vfg ( dT ) (dP )sat hfg
The calculations of the point of pressure equals 3.9 bar is briefly shown here :
Table (2 ) : Saturated Water and Steam Table hfg Vg
T (C )
P (bar)
2164
0.6057
133.5
3 hfg* Vg*
T*
3.9
2134
0.4623
143.6
4
By interpolation we get : oC T* = 142.59
Vg* = 0.4766