By placing atoms of a metal into a flame, electrons can be induced to absorb energy and jump to an excited energy state, this is called a quantum jump. They then return to their ground state by emitting a photon of light. The amount of energy in the photon of light determines its color. For example, when a photon gives off red light, you can determine that it does not have a lot of energy because red light is the lowest of visible light on the electromagnetic spectrum. Opposite to that, violet light would have the most amount of energy because it is higher up on the electromagnetic spectrum, which is because it has shorter …show more content…
Our data revealed that unknown number one was lithium chloride because of the very similar dark red color of the flame. We determined the second unknown to be strontium chloride because both flames gave off a similar bright red color. The third unknown’s flame had a very distinct salmon color, identical to the flame of potassium chloride. And the fourth unknown was barium chloride because both flames burned bright, neon