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Force Of 870n

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Force Of 870n
Chapter 5 pg 143
1. Mass 6.00 kg moved by 18.0N. What is its acceleration? Divide both sides by m

a=18N/6.00kg convert N = 18N * 1kg*m/s^2 = 18kg*m/s^2 a=18kg*m/s^2/ 6.00 kg = 3m/s^2 a=3m/s^2 7. Truck pulls trailer with friction force of 870 N and a coefficient of friction 0.23. What is the trailer’s normal force.

870N=.023(FN) divide by .023
FN=870N/.023
FN=37826.7N
9. mass 13.0 kg dropped from a cliff. Find its weight

Fw=13.0kg * 9.8m/s^2
Fw=127.4kg*m/s^2
Fw=127.4N
13. A force of 175N needed to keep a 640N engine from sliding. What is the coefficient of static friction?

Ff=175N
FN=640N
divide by 640N µ=175N/640N µ=.273
15. find acceleration of a forklift mass 1400kg pushed by force 2100N opposed by frictional force of 425N.
…show more content…
Box pushed with a force 125 N for 2.00 min. What is the impulse?

Impulse=125N*120s
Impulse=15000Ns=15000(kg*m/s^2)(s)
Impusle=15000kg*m/s
7. 15.0g bullet fired. Muzzle velocity 3250m/s from a rifle with mass 4.74kg and barrel length 75.0 cm. A) How long is bullet in barrel? d/s=t B) what is the force on the bullet while in the barrel? C) Find the bullet’s momentum as it leaves barrel. a) t=75cm/3250m/s 100cm=1m 75cm/1* 1m/100cm= .75m t=.75m/3250m/s=2.307E-4s time in barrel is 2.307E-4 seconds

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