fvs 03.07
Part I: Density of Unknown Liquid
Calculate the mass of the liquid for each trial. (Subtract the mass of the empty graduated cylinder from the mass of the graduated cylinder with liquid.)
Trial 1: Empty graduated cylinder is 25.5 subtracted from 36.5 of the liquid and the cylinder combined equals 11 grams of liquid.
Trial 2: 36 grams of water and liquid combined minus the 25.5 of the empty cylinder means equals 10.5 grams of liquid only.
Trial 3: Again 36 grams of liquid and the empty cylinder minus 25.5 grams of the empty cylinder means that there is again 10.5 grams of liquid only.
Calculate the density of the unknown liquid for each trial. (Divide the mass of the liquid calculated above by the volume of the liquid.)
Trial 1: The density of the liquid is going to be 11 grams divided by the 8.3 milliliters I got from the lab which means the density of the liquid is 1.325.
Trial 2: In trial two i calculated the mass of the liquid alone was 10.5 grams this divided by the volume which is 8.5 will give me the density which is 1.235.
Trial 3: In the last trial I got that the mass of only the liquid was 10.5 also so this divided by the volume of the liquid 8.5 will give me the same density as in trial 2 which was 1.235.
Part II: Density of Irregular-Shaped Solid
Calculate the volume of the irregular-shaped solid for each trial. (Subtract the volume of the water from the total volume of the water and solid.)
Trial 1: In trial one the volume of the water and the solid was 53.0 and the water only was 48.5 so if i subtract the volume of both by the water I get 4.5 which is the density of the object.
Trial 2: In trial two for water and solid I got 55.9 and for water I got 51.1 so I subtract smaller number from the larger one to get the density of the object which is 4.8.
Trial 3: In the last trial the combined millimeters of the water and the object was 54.0 so I need to subtract the volume of the water alone which is 49.0 so the density of the object
Calculate the mass of the liquid for each trial. (Subtract the mass of the empty graduated cylinder from the mass of the graduated cylinder with liquid.)
Trial 1: Empty graduated cylinder is 25.5 subtracted from 36.5 of the liquid and the cylinder combined equals 11 grams of liquid.
Trial 2: 36 grams of water and liquid combined minus the 25.5 of the empty cylinder means equals 10.5 grams of liquid only.
Trial 3: Again 36 grams of liquid and the empty cylinder minus 25.5 grams of the empty cylinder means that there is again 10.5 grams of liquid only.
Calculate the density of the unknown liquid for each trial. (Divide the mass of the liquid calculated above by the volume of the liquid.)
Trial 1: The density of the liquid is going to be 11 grams divided by the 8.3 milliliters I got from the lab which means the density of the liquid is 1.325.
Trial 2: In trial two i calculated the mass of the liquid alone was 10.5 grams this divided by the volume which is 8.5 will give me the density which is 1.235.
Trial 3: In the last trial I got that the mass of only the liquid was 10.5 also so this divided by the volume of the liquid 8.5 will give me the same density as in trial 2 which was 1.235.
Part II: Density of Irregular-Shaped Solid
Calculate the volume of the irregular-shaped solid for each trial. (Subtract the volume of the water from the total volume of the water and solid.)
Trial 1: In trial one the volume of the water and the solid was 53.0 and the water only was 48.5 so if i subtract the volume of both by the water I get 4.5 which is the density of the object.
Trial 2: In trial two for water and solid I got 55.9 and for water I got 51.1 so I subtract smaller number from the larger one to get the density of the object which is 4.8.
Trial 3: In the last trial the combined millimeters of the water and the object was 54.0 so I need to subtract the volume of the water alone which is 49.0 so the density of the object