Hand Grip Dynamometer Analysis
Alison Heuchan
1003022301
KPE 161
Laboratory 1: Measurement of Muscular Force and Power
TA: Victor Chan
A) Hand Grip Dynamometer
Analysis
Table 1: Hand grip dynamometer results
Trial 1 Trial 2 Trial 3 Peak
Force (kg) Left Hand 30 kg 30 kg 26 kg 30 kg
Right hand 32 kg 32 kg 30 kg 32 kg
Discussion
1. In completing this test you did repeated trials. Why might scores on a test improve as you do repeated trials?
One reason that test scores might improve as you do repeated trials is that there is a learning curve to the test. In the first few trials, the participant may not be used to the motion of the hand grip dynamometer, and so the trials could lack in force. It may be that only after a few trials the participant is able to carry out …show more content…
Does strength play a role in this test?
Strength does play a role in this test. This is a test of power, and power is equal to force times velocity. If strength is the ability to generate force, then, ultimately, strength does play a role in power. If the participant was exerting a lot of force, due to being strong, but was not able to go quickly, however, their power would still be very low. In that way, strength only partially plays a role in this test.
2. What factors could the subject change through training to improve their peak power? Think of Power equation derived in class.
To improve peak power, the subject should work on changing the amount of force they are able to generate (improve their strength), but also improve the velocity at which they can generate that force.
C) Vertical Jump.
Analysis
Table 5: Squat Jump measurements
Person Body Mass (kg) Trial 1. Jump Height (cm) Trial 2. Jump Height (cm) Trial 3. Jump Height (cm) Best Difference (cm) Calculated Leg Power from Equation 7
(Watts)
1 67 73.66 73.66 72.39 73.66 5775.31
2 63.5 53.34 55.88 55.88 55.88 …show more content…
Jump Height (cm) Trial 2. Jump Height (cm) Trial 3. Jump Height (cm) Best Difference (cm) Calculated Leg Power from Equation 7
(Watts)
1 67 74.93 72.39 74.93 74.93 5875.01
2 63.5 58.42 59.69 63.5 63.5 4649.06
Calculated leg power:
Ppeak(W) = 78.5 x 74.93 cm + 60.6 x 67 kg - 15.3 x 180.34 cm - 1308
= 5882.01 + 4060.2 - 2759.202 - 1308 = 5875.01
Ppeak(W) = 78.5 x 63.5 cm + 60.6 x 63.5 kg - 15.3 x 187.96 cm - 1308
= 4984.75 + 3848.1 - 2875.79 - 1308 = 4649.06
Discussion
1. Compare the peak power value obtained during the Wingate test to the peak power value calculated from the vertical jump equation 7. Why would there be a difference? If you didn’t do the Wingate use the data from someone else who did?
Peak power value was considerably higher in the vertical jump test. The difference is a result of the jump having a very high velocity as well as force, which results in high peak power. The jump takes place over a very short period of time. The wingate test, however, takes place over a much longer period of time. In the vertical jump, the body can use up a large amount of energy at once. In the wingate test, the body must sustain energy over that longer period of
1003022301
KPE 161
Laboratory 1: Measurement of Muscular Force and Power
TA: Victor Chan
A) Hand Grip Dynamometer
Analysis
Table 1: Hand grip dynamometer results
Trial 1 Trial 2 Trial 3 Peak
Force (kg) Left Hand 30 kg 30 kg 26 kg 30 kg
Right hand 32 kg 32 kg 30 kg 32 kg
Discussion
1. In completing this test you did repeated trials. Why might scores on a test improve as you do repeated trials?
One reason that test scores might improve as you do repeated trials is that there is a learning curve to the test. In the first few trials, the participant may not be used to the motion of the hand grip dynamometer, and so the trials could lack in force. It may be that only after a few trials the participant is able to carry out …show more content…
Does strength play a role in this test?
Strength does play a role in this test. This is a test of power, and power is equal to force times velocity. If strength is the ability to generate force, then, ultimately, strength does play a role in power. If the participant was exerting a lot of force, due to being strong, but was not able to go quickly, however, their power would still be very low. In that way, strength only partially plays a role in this test.
2. What factors could the subject change through training to improve their peak power? Think of Power equation derived in class.
To improve peak power, the subject should work on changing the amount of force they are able to generate (improve their strength), but also improve the velocity at which they can generate that force.
C) Vertical Jump.
Analysis
Table 5: Squat Jump measurements
Person Body Mass (kg) Trial 1. Jump Height (cm) Trial 2. Jump Height (cm) Trial 3. Jump Height (cm) Best Difference (cm) Calculated Leg Power from Equation 7
(Watts)
1 67 73.66 73.66 72.39 73.66 5775.31
2 63.5 53.34 55.88 55.88 55.88 …show more content…
Jump Height (cm) Trial 2. Jump Height (cm) Trial 3. Jump Height (cm) Best Difference (cm) Calculated Leg Power from Equation 7
(Watts)
1 67 74.93 72.39 74.93 74.93 5875.01
2 63.5 58.42 59.69 63.5 63.5 4649.06
Calculated leg power:
Ppeak(W) = 78.5 x 74.93 cm + 60.6 x 67 kg - 15.3 x 180.34 cm - 1308
= 5882.01 + 4060.2 - 2759.202 - 1308 = 5875.01
Ppeak(W) = 78.5 x 63.5 cm + 60.6 x 63.5 kg - 15.3 x 187.96 cm - 1308
= 4984.75 + 3848.1 - 2875.79 - 1308 = 4649.06
Discussion
1. Compare the peak power value obtained during the Wingate test to the peak power value calculated from the vertical jump equation 7. Why would there be a difference? If you didn’t do the Wingate use the data from someone else who did?
Peak power value was considerably higher in the vertical jump test. The difference is a result of the jump having a very high velocity as well as force, which results in high peak power. The jump takes place over a very short period of time. The wingate test, however, takes place over a much longer period of time. In the vertical jump, the body can use up a large amount of energy at once. In the wingate test, the body must sustain energy over that longer period of