Hardy Weinberg Sheet
Biology
Hardy-Weinberg Lab
Using the Hardy-Weinberg equation, calculate the predicted genotype frequencies for each population scenario below. Place your calculations and data in the space provided below. Once you have calculated the frequencies, answer the conclusion questions for each one. Please remember that all calculations must be shown for full credit.
Scenario #1
In the year 2050, humans have successfully colonized the Moon. The lunar modules created for this purpose could only house a small population of people. It is now a century later and the population has grown to 4,000 people. In the current Moon population, 10 people express the recessive phenotype for cystic fibrous (cc genotype). q2 – 10/4000 = 0.0025 q – √0.0025 = 0.05 p – 1- 0.05 = 0.95 p2 – = 0.9025
2pq – 2 x (0.95) x (0.05) = 0.095
Conclusion Questions
Use this information to help you answer the following questions:
The original population’s actual genotype frequencies were:
CC – 0.73; Cc – 0.19; cc – 0.08
1) Is the current population in Hardy-Weinberg equilibrium? No
2) Is the current population evolving? Yes
3) If the current population is evolving, what type of effect is responsible for genetic drift?
The population is evolving toward normal, since CC and Cc are increasing and cc is decreasing. It is most likely that the founder effect is going to take place.
Scenario #2
Jan Mayen Island is a tiny island in the Arctic Ocean, approximately 400 miles northeast of Iceland. It had an original population of 1,000, but due to a series of volcanic eruptions and earthquakes in the year 2010, much of the island’s population was killed, leaving only 200. It is now 80 years later and the population on Jan Mayen Island has reached 500. In the current population, 20 people are homozygous recessive for hemophilia C, which is autosomal (hh genotype).
q2 – 20/500 = 0.04 q – 0.04 = 0.2 p – 1- 0.2 = 0.8 p2 – = 0.64
2pq –2 x (0.8) x
Hardy-Weinberg Lab
Using the Hardy-Weinberg equation, calculate the predicted genotype frequencies for each population scenario below. Place your calculations and data in the space provided below. Once you have calculated the frequencies, answer the conclusion questions for each one. Please remember that all calculations must be shown for full credit.
Scenario #1
In the year 2050, humans have successfully colonized the Moon. The lunar modules created for this purpose could only house a small population of people. It is now a century later and the population has grown to 4,000 people. In the current Moon population, 10 people express the recessive phenotype for cystic fibrous (cc genotype). q2 – 10/4000 = 0.0025 q – √0.0025 = 0.05 p – 1- 0.05 = 0.95 p2 – = 0.9025
2pq – 2 x (0.95) x (0.05) = 0.095
Conclusion Questions
Use this information to help you answer the following questions:
The original population’s actual genotype frequencies were:
CC – 0.73; Cc – 0.19; cc – 0.08
1) Is the current population in Hardy-Weinberg equilibrium? No
2) Is the current population evolving? Yes
3) If the current population is evolving, what type of effect is responsible for genetic drift?
The population is evolving toward normal, since CC and Cc are increasing and cc is decreasing. It is most likely that the founder effect is going to take place.
Scenario #2
Jan Mayen Island is a tiny island in the Arctic Ocean, approximately 400 miles northeast of Iceland. It had an original population of 1,000, but due to a series of volcanic eruptions and earthquakes in the year 2010, much of the island’s population was killed, leaving only 200. It is now 80 years later and the population on Jan Mayen Island has reached 500. In the current population, 20 people are homozygous recessive for hemophilia C, which is autosomal (hh genotype).
q2 – 20/500 = 0.04 q – 0.04 = 0.2 p – 1- 0.2 = 0.8 p2 – = 0.64
2pq –2 x (0.8) x