Hydrate Lab
Abstract:
Hydrates are compound with a constant composition. Concepts of Law of Definite Proportions (hydrates remain in constant proportions) and Law of Conservation of Mass (this idea is used to determine the mass of water in the compound and, subsequently, the formula of the compound) are expressed in this experiment. In this experiment, the goal was to find the formula of copper sulfate pentahydrate by heating a sample of the blue compound in order to evaporate the water and receive the white-colored copper sulfate anhydrous. Using the mass of the original sample of copper sulfate pentahydrate subtracted by the new mass of the copper sulfate anhydrous, the mass of water lost is obtained and used to find the empirical formula. The expectation for …show more content…
Add hydrate to the crucible
6. Weigh crushed hydrate
7. Light Bunsen burner
8. Adjust ring stand and heat the hydrate until it turns white/gray
9. Cool then weigh the crucible
Data:
Mass of crucible 23.15 grams
Mass of Crucible with crushed hydrate 29.62 grams
Mass of crushed hydrate 6.47 grams
Mass of crucible with crushed hydrate after heating 26.64 grams
Mass of crushed hydrate after heating 3.49 grams
Therefore, mass of Water that has escaped = (mass of crushed hydrate) - (mass of crushed hydrate after heating)
Mass of H2O = 2.98 grams
Therefore mols of H2O = (2.98g) * (1mol)\(18g) = .165 mols H2O
So, mols of Cu2SO4 = (3.49g) * (1mol)\(223.15g) = .015 mols Cu2SO4
Divide by .015
Common ratio:
Cu2SO4 = 1
H2O = 10
Therefore, empirical formula of Cu2SO4 . H2O should be: Cu2SO4 . 10H2O
Conclusion:
A hydrate is a substance that holds water in a certain ratio. As Hydrates are compounds with constant composition, we were able to easily determine this ratio by evaporating the water and then calculating a common ratio. We had Copper sulfate pentahydrous. In our experiment and on further calculations we observed that generally ten molecules of water combine with one molecule of
Hydrates are compound with a constant composition. Concepts of Law of Definite Proportions (hydrates remain in constant proportions) and Law of Conservation of Mass (this idea is used to determine the mass of water in the compound and, subsequently, the formula of the compound) are expressed in this experiment. In this experiment, the goal was to find the formula of copper sulfate pentahydrate by heating a sample of the blue compound in order to evaporate the water and receive the white-colored copper sulfate anhydrous. Using the mass of the original sample of copper sulfate pentahydrate subtracted by the new mass of the copper sulfate anhydrous, the mass of water lost is obtained and used to find the empirical formula. The expectation for …show more content…
Add hydrate to the crucible
6. Weigh crushed hydrate
7. Light Bunsen burner
8. Adjust ring stand and heat the hydrate until it turns white/gray
9. Cool then weigh the crucible
Data:
Mass of crucible 23.15 grams
Mass of Crucible with crushed hydrate 29.62 grams
Mass of crushed hydrate 6.47 grams
Mass of crucible with crushed hydrate after heating 26.64 grams
Mass of crushed hydrate after heating 3.49 grams
Therefore, mass of Water that has escaped = (mass of crushed hydrate) - (mass of crushed hydrate after heating)
Mass of H2O = 2.98 grams
Therefore mols of H2O = (2.98g) * (1mol)\(18g) = .165 mols H2O
So, mols of Cu2SO4 = (3.49g) * (1mol)\(223.15g) = .015 mols Cu2SO4
Divide by .015
Common ratio:
Cu2SO4 = 1
H2O = 10
Therefore, empirical formula of Cu2SO4 . H2O should be: Cu2SO4 . 10H2O
Conclusion:
A hydrate is a substance that holds water in a certain ratio. As Hydrates are compounds with constant composition, we were able to easily determine this ratio by evaporating the water and then calculating a common ratio. We had Copper sulfate pentahydrous. In our experiment and on further calculations we observed that generally ten molecules of water combine with one molecule of