Incline Motion Lab
Incline Lab
Purpose – The purpose of this experiment was to find how position and time are related to a ball on an incline.
Data –
7 Books X (cm) | Trial 1 (s) | Trial 2 (s) | Trial 3 (s) | Average (s) | 10 | 0.336 | 0.3654 | 0.3434 | 0.3479 | 15 | 0.3952 | 0.4262 | 0.43 | 0.4171 | 50 | 0.9127 | 0.8846 | 0.8936 | 0.8971 | 75 | 1.1257 | 1.1178 | 1.1322 | 1.1252 | 100 | 1.320 | 1.2788 | 1.2979 | 1.2989 | 125 | 1.4924 | 1.4966 | 1.4766 | 1.4885 |
4 Books X (cm) | Trial 1 (s) | Trial 2 (s) | Trial 3 (s) | Average (s) | 10 | 0.4663 | 0.4540 | 0.4664 | 0.4622 | 15 | 0.5559 | 0.5716 | 0.5838 | 0.5715 | 50 | 1.1117 | 1.1721 | 1.1337 | 1.1391 | 75 | 1.4165 | 1.4153 | 1.4231 | 1.4183 | 100 | 1.6859 | 1.6683 | 1.6509 | 1.6682 | 125 | 1.9305 | 1.9851 | 1.9604 | 1.9587 |
We found the average by using the formula (Trial 1 +Trial 2 + Trial 3)/3, and example would be (0.4663+0.454+0.4664)/3 = (1.3867)/3 = 0.4622 seconds.
Graphs - The graphs (stapled on the back) all display that the ball moves at a constant acceleration.
4 book x-t graph: P= 32.38cm/s2 (t) + 6.012cm
7 book v-t graph: V= 52.19cm/s2 (t) + 54.74s
7 book x-t graph: P= 55.09cm/s2 (t) + 4.948cm
4 book v-t graph:
The position vs. time graphs’ (x-t) slopes represent velocity. Obviously, 7 books will have a higher velocity than 4 books, thus having a larger slope (32.38cm/s2 vs. 55.09cm/s2). The y-intercept represents the place where we started the ball on the ramp. The velocity vs time graphs’ (v-t) slopes represent acceleration. To find instantaneous velocity, you have to find the slope of all the points on the v-t graph and use the slopes of all the points as the points in the acceleration vs. time graph.
Conclusion – In this lab I have learned that an object going down an incline will accelerate at a constant rate and moves faster every second. The position vs. time squared graphs’ equation is ½ the slope of the acceleration vs. time graph because you have to use time
Purpose – The purpose of this experiment was to find how position and time are related to a ball on an incline.
Data –
7 Books X (cm) | Trial 1 (s) | Trial 2 (s) | Trial 3 (s) | Average (s) | 10 | 0.336 | 0.3654 | 0.3434 | 0.3479 | 15 | 0.3952 | 0.4262 | 0.43 | 0.4171 | 50 | 0.9127 | 0.8846 | 0.8936 | 0.8971 | 75 | 1.1257 | 1.1178 | 1.1322 | 1.1252 | 100 | 1.320 | 1.2788 | 1.2979 | 1.2989 | 125 | 1.4924 | 1.4966 | 1.4766 | 1.4885 |
4 Books X (cm) | Trial 1 (s) | Trial 2 (s) | Trial 3 (s) | Average (s) | 10 | 0.4663 | 0.4540 | 0.4664 | 0.4622 | 15 | 0.5559 | 0.5716 | 0.5838 | 0.5715 | 50 | 1.1117 | 1.1721 | 1.1337 | 1.1391 | 75 | 1.4165 | 1.4153 | 1.4231 | 1.4183 | 100 | 1.6859 | 1.6683 | 1.6509 | 1.6682 | 125 | 1.9305 | 1.9851 | 1.9604 | 1.9587 |
We found the average by using the formula (Trial 1 +Trial 2 + Trial 3)/3, and example would be (0.4663+0.454+0.4664)/3 = (1.3867)/3 = 0.4622 seconds.
Graphs - The graphs (stapled on the back) all display that the ball moves at a constant acceleration.
4 book x-t graph: P= 32.38cm/s2 (t) + 6.012cm
7 book v-t graph: V= 52.19cm/s2 (t) + 54.74s
7 book x-t graph: P= 55.09cm/s2 (t) + 4.948cm
4 book v-t graph:
The position vs. time graphs’ (x-t) slopes represent velocity. Obviously, 7 books will have a higher velocity than 4 books, thus having a larger slope (32.38cm/s2 vs. 55.09cm/s2). The y-intercept represents the place where we started the ball on the ramp. The velocity vs time graphs’ (v-t) slopes represent acceleration. To find instantaneous velocity, you have to find the slope of all the points on the v-t graph and use the slopes of all the points as the points in the acceleration vs. time graph.
Conclusion – In this lab I have learned that an object going down an incline will accelerate at a constant rate and moves faster every second. The position vs. time squared graphs’ equation is ½ the slope of the acceleration vs. time graph because you have to use time