Unit 8 Labs
Lab 8.1: IP Addressing and Classes: Exercises 8.1.1, 8.1.2, 8.1.3, 8.1.4, 8.1.5, 8.1.6
LAB8.1.1) Network ID is 110| Host id is 10.10.1|Network ID binary is 01101110 Host ID is 00001010.00001010.00000001
Lab 8.1.2) Class | Range of first byte (Octet) In Decimal | Network ID | Host ID | Possible Networks | Possible Host Per Network | | A | 0-127.255.255.255 | A | B,C,D | 128 | 16,777,216 | B | 128-191.255.255.255 | A,B | C,D | 16,384 | 65,536 | C | 192-223.255.255.255 | A,B,C | D | 2,097,152 | 256 |
The number isn’t equal to 2 raised to the power of the number of bits because you always have to take away 2 from the network for the network and broadcast address
Lab 8.1.3)No it would not be justified as a class c address because it is within the range for a class A address but it can be subnetted as a class C
Lab 8.1.4)The network Id according to the subnet is 190.8|The host ID is .8.4|The binary network ID is10111110.00001000|The binary host ID is 00001000.00000100 | Yes it does the subnet matches to the IP address and class.
Lab 8.1.5)The Slash notation for the Subnet is /24| the slash is /9 and the way I found out is looking at the webpages that were provided.
Lab 8.1.6) Block size | Starting IP | Ending IP | Subnet Mask(slash Notation) | | 24 | 10.0.0.0 | 10.255.255.255 | 255.0.0.0|/8 | 20 | 172.16.0.0 | 172.31.255.255 | 255.0.0.0-255.255.0.0/8-/16 | 16 | 192.168.0.0 | 192.168.255.255 | 255.255.0.0-255.255.255.0|/16-/24 |
Lab 8.2: Assigning Static IP Addresses: Exercise 8.2.1
Lab 8.3: Routing Tables: Exercises 8.3.1, 8.3.2, 8.3.3
Lab 8.4: SOHO Planning: Exercises 8.4.1,