1/T
Uncertainty of 1/T
0.26136
6%
0.003309
0.0034%
-0.10536
6%
0.003301
0.0033%
0.139762
4%
0.003288
0.0032%
0.34359
4%
0.003279
0.0031%
0.625938
3%
0.003266
0.0029%
1.011601
2%
0.003259
0.0029%
1.105257
2%
0.003256
0.0029%
1.348073
1%
0.00325
0.0028%
1.824549
0.81%
0.003213
0.0026%
1) Calculating the uncertainty
i) Uncertainty for ln(k)
Eg: ln(k)= 0.26136
Uncertainty= ((0.05)/ (0.26136))100
Uncertainty=> +/- 6%
ii) Uncertainty for 1/T
Eg: 1/T= 0.003309
Uncertainty= (0.000001/ 0.003309)100
Uncertainty=> 0.0034%
Graph:
1) Determining the activation energy of a light stick
i) In order to find the activation energy, we must find the slope
Slope= -23616 K
ii) Now plug the values into the equation below
Ea= (-R)(slope)
Where Ea is the activation energy, R is the rate constant (8.314 J/mol*K)
Ea= -8.314 (-23616)
Ea= 196343.6 J/mol
Ea= 196.3 kJ/mol
Ea= 196 kJ/mol +/- 0.51%
iii) Calculating the maximum and minimum values
Maximum: 188 kJ/mol
Minimum: 173 kJ/mol
2) Determining the percent error
Theoretical value: 195 kJ/mol
Percent error= | (theoretical-experimental) / (theoretical) |*100
Percent error= | (195-196) / (195) |*100
Percent error=> +/- 0.51%
Percent error= | (theoretical-experimental) / (theoretical) |*100
Percent error= | (195-196) / (195) |*100
Percent error=> +/- 0.51%
Percent error= | (theoretical-experimental) / (theoretical) |*100
Percent error= | (195-196) / (195) |*100
Percent error=> +/- 0.51%
Percent error= | (theoretical-experimental) / (theoretical) |*100
Percent error= | (195-196) / (195) |*100
Percent error=> +/- 0.51%
Percent error= | (theoretical-experimental) / (theoretical) |*100
Percent error= | (195-196) / (195) |*100
Percent error=> +/- 0.51%
Percent error= | (theoretical-experimental) / (theoretical) |*100