Lolicon Slayer Johnson
1)
Objective
Investigate the velocity immediately after the collision.
Givens
SUV: 3000 kg; Accleration of SUV brake locked: 2 m/s 2
Subaru: 2000 kg; Accleration of Subaru braked locked : 3 m/s 2
The initial velocity of Subaru is 0 m/s speed limit: 35 km/hr distance traveled after collision: 22 m
unknown
the initial velocity after collision
theory and equation Elasticity of collision
Kinematics
1 a • d = V f 2 − V i 2
2
assumption
the final velocity after they collide and traveled 22 m is 0.
Work
F1+F2 = Ffinal
F final = 3000kg • (− 2m/s 2) + 2000kg • (− 3m/s 2) =− 12000N
a final =
−12000N
5000 kg
=− 2.4m/s 2
• (− 2.4m/s 2) • 22m = 0 2 − V i 2
V i = 10.276 m/s Vi is the velocity immediately after the collision.
1
2
diagram
2)
Objective
Determine the initial velocity of SUV before collision
Givens Variables
M1 : SUV: 3000 kg; Accleration of SUV brake locked: 2 m/s 2
M2 : Subaru: 2000 kg; Accleration of Subaru braked locked : 3 m/s 2
The initial velocity of Subaru is 0 m/s speed limit: 35 km/hr distance traveled after collision: 22 m
Vi velocity immediately after collision: 10.276 m/s
V2 velocity of Subaru before collision
Unknowns
Variables
V1 initial velocity of SUV before collision
Theory/Equations
/Laws
momentum law of conservation of energy
M 1 • V 1 + M 2 • V 2 = M total • V i
Assumptions
since this is an elastic collision, the Pi = Pf, energy is conserved.
Work
Pi=Pf
M 1 • V 1 + M 2 • V 2 = M total • V i
3000kg x V1i + 2000kg x
Diagrams
3) Since after the collision, the SUV sticks into the Outback Wagon and moves together, there for the collision is an elastic collision, and there is no kinetic energy lost in the collision.
Objective
Investigate the velocity immediately after the collision.
Givens
SUV: 3000 kg; Accleration of SUV brake locked: 2 m/s 2
Subaru: 2000 kg; Accleration of Subaru braked locked : 3 m/s 2
The initial velocity of Subaru is 0 m/s speed limit: 35 km/hr distance traveled after collision: 22 m
unknown
the initial velocity after collision
theory and equation Elasticity of collision
Kinematics
1 a • d = V f 2 − V i 2
2
assumption
the final velocity after they collide and traveled 22 m is 0.
Work
F1+F2 = Ffinal
F final = 3000kg • (− 2m/s 2) + 2000kg • (− 3m/s 2) =− 12000N
a final =
−12000N
5000 kg
=− 2.4m/s 2
• (− 2.4m/s 2) • 22m = 0 2 − V i 2
V i = 10.276 m/s Vi is the velocity immediately after the collision.
1
2
diagram
2)
Objective
Determine the initial velocity of SUV before collision
Givens Variables
M1 : SUV: 3000 kg; Accleration of SUV brake locked: 2 m/s 2
M2 : Subaru: 2000 kg; Accleration of Subaru braked locked : 3 m/s 2
The initial velocity of Subaru is 0 m/s speed limit: 35 km/hr distance traveled after collision: 22 m
Vi velocity immediately after collision: 10.276 m/s
V2 velocity of Subaru before collision
Unknowns
Variables
V1 initial velocity of SUV before collision
Theory/Equations
/Laws
momentum law of conservation of energy
M 1 • V 1 + M 2 • V 2 = M total • V i
Assumptions
since this is an elastic collision, the Pi = Pf, energy is conserved.
Work
Pi=Pf
M 1 • V 1 + M 2 • V 2 = M total • V i
3000kg x V1i + 2000kg x
Diagrams
3) Since after the collision, the SUV sticks into the Outback Wagon and moves together, there for the collision is an elastic collision, and there is no kinetic energy lost in the collision.