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Mat 540 Final

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Mat 540 Final
Chapter 1 - Section 1.1

Write the interval of real numbers in interval notation and graph it. See Example 5.

50. The set of real numbers less than or equal to -4

Consider the following nine integers:
-4, -3, -2, -1, 0, 1, 2, 3, 4

94. Which of these integers has an absolute value greater than 1?

Solution:

-4, -3, -2, 2, 3, 4

Write the interval notation for the interval of real numbers shown in the graph.

__________________ -50 -40 -30 -20 -10 0 A B

Hint: replace a with (-3) and evaluate each expression. Which are positive and which negative?

(a) -3 solution: positive (b)|-3| solution: positive

(c)-|3| solution: negative
…show more content…
(-8)(-6) = 48

Perform the indicated operations and reduce to lowest terms.

-9/10 x4/3

Solution:

= - 36/30 = -6/5

Fill in the correct value in the parentheses so the equation is correct.

-48 divided by ( )=6

-48/ x = 6

 -48 = 6x
 x = -48/6 = -8

Therefore, -48 (-8) = 6

Chapter 1 - Section 1.5

Evaluate the expression using order of operations.. See Example 8.

3[(2-3)^2 +6(6-4)^2]

= 3[(-1)^2 + 6*(2)^2]

= 3[1 + 24] = 3*25 = 75

Evaluate each expression using order of operations.. See Example 8 a)

8 – 3 |5 - 4 + 1 |

= 8 – 3|5-16+ 1|
= 8 – 3|-10| = 8-3*10 = 8 – 30 = -22

Chapter 1 - Section 1.6

Evaluate each expression using a = -1, b = 2, and c = -3.
See Example 4.

(a – c)(a + c) = a^2 – c^2 = (-1)^2 – (-3)^2 = 1 – 9 = -8

Determine whether the given number is a solution to the equation following it. See Example 5.

Let us substitute x = 5 in the given equation, we will get

3(5) + 7 = 2(5) – 1
15 + 7 = 9
22 = 9

Which is not

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