Math 133 Unit2

Math 133
Unit 2 IP2

1. X^2-10x-24
a) X=4 x= -6

Show my work:
X^2-10x-24=0
A) 1 B) -10 C) -24
X^2-10x-24=0
(X-4) (x+6)
X-4=0 x=4 x+6=0 x= -6

B) 3x^2+7x-20=0
Answer: x=7+4=5.5 x= 7-4=1.5

Show my work:
X= -b±b2-4ac2a
X= (-7) ±(-7)2-4(3)(20)2a
X= 7±64-802a
X=7 ±-16
X=7+4/2=5.5
X=7-4/2=1.5

c.10x^2+x-3=0 x=-b±b2-4ac2a x=-1±(1)2-4(10)(-3)2(10)

x=1±1-12020

x=1±10 x=1+320 = 5 x=1-320= 10

There are two types of solutions to this problem which are x=1+320 = 5 and x=1-320= 10

2.
a. The solution for this equation just by looking at the graph is (-2.3,0) and (0,6.3)
b. This is a maximum function. The reason how I obtain my answer is because it is at the peak of the parabola
c. (2, 9)
d. the equation is x=2

3.
a. s= -16t^2+64t+25
b. 73 Feet
Show my work:
S= -16◦(1)^2+64◦(1)+25
S= -16+64+25
S=73 feet

C Answer is 2 seconds

Show my work:
.-b2a= -642(-16)= -64/-32=2 seconds

d. Answer is 89 feet

Show my work
S= -16*(2)^2+64*(2)+25
S= 64+128+25= 89 feet

4. a.

x | y | -2 | 4 | -1 | 0 | 0 | -2 | 1 | -2 | 2 | 0 | 3 | 4 |
Show my work

Y=x^2-x-2
X=-2 x= -1 x=0 x=1
Y=-2^2-(-2)-2 y= -1^2-(-1)-2 y= 0^2-0-2 y=1^2-1-2
Y=4+2-2 y= 1+1 -2 y= -2 y= 1-1-2
Y=6-2 y= 2-2 y= 0-2
Y=4 y=0 y= -2

X=2 x=3
Y=2^2-2-2 y=3^2-3-2
Y=4-2-2 y=9-3-2
Y=2-2