MATH533 Course Project Paper B
The average (mean) annual income was less than $50,000,
One-Sample Z: Income ($1000)
Test of mu = 50 vs < 50
The assumed standard deviation = 14.64
95% Upper
Variable N Mean StDev SE Mean Bound Z P
Income ($1000) 50 43.74 14.64 2.07 47.15 -3.02 0.001
α 0.05= -1.645
H0 μ = 50,000
Ha μ < 50,000
The hypothesis test claims that the average annual income was less than $50,000. H0 claims equal to $50,000 and the alternative hypothesis claims less than $50,000. The significance level is α 0.05= -1.645. According to Course Project data, when I generate the data of income in Minitab, I found the standard deviation, which is 14.64. Then next step is calculating the z-value by Minitab, which is -3.02.
Consequently;
z-value < α 0.05 -3.020.4
The hypothesis test claims that the true population proportion of customers who live in urban area is greater than %40. H0 claims equal to %40 and the alternative hypothesis claims less than %40. The significance level is α 0.05= 1.645. According to Course Project data, when I generate the data of income in Minitab, I calculated the number of trails and event respectively. The number of trails is 66 and events is 171. Then next step is calculating the proportion by Minitab, which is -0.37.
Consequently;
-0.37 significance level.
The average (mean) number of years lived in the current home is less than 13 years,
One-Sample Z: Years
Test of mu = 13 vs < 13
The assumed standard deviation = 5.086
95% Upper
Variable N Mean StDev SE Mean Bound Z P
Years 50 12.260 5.086 0.719 13.443 -1.03 0.152
α 0.05= -1.645
H0 μ = 13
Ha μ < 13
The hypothesis test claims that the average number of years lived in the current home is less than 13 years. H0 claims equal to 13 years and the alternative hypothesis claims less
One-Sample Z: Income ($1000)
Test of mu = 50 vs < 50
The assumed standard deviation = 14.64
95% Upper
Variable N Mean StDev SE Mean Bound Z P
Income ($1000) 50 43.74 14.64 2.07 47.15 -3.02 0.001
α 0.05= -1.645
H0 μ = 50,000
Ha μ < 50,000
The hypothesis test claims that the average annual income was less than $50,000. H0 claims equal to $50,000 and the alternative hypothesis claims less than $50,000. The significance level is α 0.05= -1.645. According to Course Project data, when I generate the data of income in Minitab, I found the standard deviation, which is 14.64. Then next step is calculating the z-value by Minitab, which is -3.02.
Consequently;
z-value < α 0.05 -3.020.4
The hypothesis test claims that the true population proportion of customers who live in urban area is greater than %40. H0 claims equal to %40 and the alternative hypothesis claims less than %40. The significance level is α 0.05= 1.645. According to Course Project data, when I generate the data of income in Minitab, I calculated the number of trails and event respectively. The number of trails is 66 and events is 171. Then next step is calculating the proportion by Minitab, which is -0.37.
Consequently;
-0.37 significance level.
The average (mean) number of years lived in the current home is less than 13 years,
One-Sample Z: Years
Test of mu = 13 vs < 13
The assumed standard deviation = 5.086
95% Upper
Variable N Mean StDev SE Mean Bound Z P
Years 50 12.260 5.086 0.719 13.443 -1.03 0.152
α 0.05= -1.645
H0 μ = 13
Ha μ < 13
The hypothesis test claims that the average number of years lived in the current home is less than 13 years. H0 claims equal to 13 years and the alternative hypothesis claims less