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Mecatronics
Solutions Manual

INTRODUCTION TO
MECHATRONICS AND
MEASUREMENT
SYSTEMS
3rd edition

SOLUTIONS MANUAL

David G. Alciatore and Michael B. Histand

Department of Mechanical Engineering
Colorado State University
Fort Collins, CO 80523

Introduction to Mechatronics and Measurement Systems

1

Solutions Manual

This manual contains solutions to the end-of-chapter problems in the third edition of
"Introduction to Mechatronics and Measurement Systems." Only a few of the open-ended problems that do not have a unique answer are left for your creative solutions. More information, including an example course outline, a suggested laboratory syllabus, MathCAD files for examples in the book, and other supplemental material are provided on the Internet at: www.engr.colostate.edu/mechatronics We have class-tested the textbook for several years, and it should be relatively free from errors. However, if you notice any errors or have suggestions or advice concerning the textbook's content or approach, please feel free to contact us via e-mail at David.Alciatore@colostate.edu.
We will post corrections for reported errors on our Web site.
Thank you for choosing our book. We hope it helps you provide your students with an enjoyable and fruitful learning experience in the cross-disciplinary subject of mechatronics.

2

Introduction to Mechatronics and Measurement Systems

Solutions Manual
2.1

D = 0.06408 in = 0.001628 m.
2

–6 πD A = --------- = 2.082 × 10
4

ρ = 1.7 x 10-8 Ωm, L = 1000 m
R = ρL = 8.2Ω
-----A
2.2
4

(a)

R 1 = 21 × 10 ± 20% so 168kΩ ≤ R 1 ≤ 252kΩ

(b)

R 2 = 07 × 10 ± 20% so 5.6kΩ ≤ R 2 ≤ 8.4kΩ

(c)

R s = R 1 + R 2 = 217kΩ ± 20% so 174kΩ ≤ R s ≤ 260kΩ

(d)

R1 R2
R p = -----------------R1 + R2

3

R 1MIN R 2MIN
R pMIN = ------------------------------- = 5.43kΩ
R 1MIN + R 2 MIN
R 1MAX R 2MAX
R pMAX = --------------------------------- = 8.14kΩ
R 1 MAX + R 2 MAX
2.3

2

R 1 = 10 × 10 ,

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