1. The sample size for this sample survey appears to be a) 400 b) 2,800,000 c) 144 d) 1,008,000
2. The 36% is a a) Parameter b) Margin of error c) Chance of 144 people agreeing to the statement d) Statistic
3. Event A occurs with probability 0.05. Event B occurs with probability …show more content…
0.75. If A and B are disjoint, which statement is true? a) P(A and B) = 0 b) P(A or B) = 0.80 c) P(A and B) = 0.0375 d) Both (a) and (b) are true.
4. Event A occurs with probability 0.05. Event B occurs with probability 0.75. If A and B are independent, which statement is true. e) P(A and B) = 0 a) P(A or B) = 0.80 b) P(A and B) = 0.0375 c) Both (a) and (b) are true.
A marketing research firm wishes to determine if the adult men in Laramie, Wyoming would be interested in a new upscale men's clothing store. From a list of all residential addresses in Laramie, the firm selects a simple random sample of 100 and mails a brief questionnaire to each. Use this information to answer the next three questions.
5. The population of interest is a) all adult men in Laramie, Wyoming. b) all residential addresses in Laramie, Wyoming. c) the members of the marketing firm that actually conducted the survey. d) the 100 addresses to which the survey was mailed.
6. The sample in this survey is a) all adult men in Laramie, Wyoming. b) all residential addresses in Laramie, …show more content…
Wyoming. c) the members of the marketing firm that actually conducted the survey. d) the 100 addresses to which the survey was mailed.
7. The chance that all 100 homes in a particular neighborhood in Laramie end up being the sample of residential addresses selected is a) the same as for any other set of 100 residential addresses. b) exactly 0. Simple random samples will spread out the addresses selected. c) reasonably large due to the “cluster” effect. d) 100 divided by the size of the population of Laramie.
Costs for standard veterinary services at a local animal hospital follow a Normal distribution with a mean of $80 and a standard deviation of $20. Answer the next three questions.
8. Give the sample space for the costs of standard veterinary services. a) {X ≥ 0} b) { 0 ≤ X ≤ 80} c) {0 ≤ X ≤ 160} d) None of these.
9. What is the probability that one bill for veterinary services costs less than $95? a) 0.75 a) 0.7734 b) 0.2266 c) 0.15
10. What is the probability that one bill for veterinary services costs between $75 and $105? a) 1 a) 0.25 b) 0.4013 c) 0.4931
11. In an instant lottery, your chances of winning are 0.2. If you play the lottery five times and outcomes are independent, what is the probability that you win at least once? a. 0.2 a) 0.08192 b) 0.32768 c) 0.67232
A commuter must pass through 4 traffic lights on her way to work, and will have to stop at each one that is red. Let the random variable be X = number of red lights. The following table is the probability distribution for X. Answer the next four questions.
|X |P(X = x) |
|0 |0.05 |
|1 |0.25 |
|2 |0.15 |
|3 |0.40 |
|4 |0.15 |
12. Give the sample space S for the number of red lights that the commuter stops at. a) {1, 2, 3, 4} b) {0, 1, 2, 3, 4} c) {0.05, 0.25, 0.15, 0.40, 0.15} d) {0, 3, 2, 3, 3, 3, 2, 4, 3, 3, 3, 2, 0, 3 }
13. What is the probability that the commuter stops at least at one red stoplight? a) 0.05 b) 0.3 c) 0.25 d) 0.95
14. What is the expected value of the number of red lights the commuter will stop at? a) 2 b) 0.2 c) 2.35 d) None of these above
6.
15. What is the standard deviation for the number of red lights the commuter will stop at? a) 1.58 b) 1.152 c) 0.132 d) None of these above
16.
Suppose this commuter is working 5 days a week. How many times during a week would she expect to stop at a red light on her way to work? a) 10 b) 2.35 c) 11.75 d) 4
17. Suppose X is a random variable with mean µX and standard deviation σX. Suppose Y is a random variable with mean µY and standard deviation σY. The mean of X + Y is a) µX + µY. b) (µX/σX) + (µY/σY). c) µX + µY, but only if X and Y are independent. d) (µX/σX) + (µY/σY), but only if X and Y are independent. 18. Suppose X is a random variable, with mean µX and standard deviation σX. Suppose Y is a random variable, with mean µY and standard deviation σY. The variance of X + Y is a) σX + σY. b) (σX)2 + (σY)2. c) σX + σY, but only if X and Y are independent. d) (σX)2 + (σY)2, but only if X and Y are independent.
Suppose the probability that a U.S. resident has traveled to Canada is P(C) = 0.18, to Mexico is P(M) = 0.09, and to both is 0.04. Use the Venn diagram to answer questions the next four questions.
19. What is the probability that an American chosen at random has traveled to either Canada or Mexico or both? a)
0.18 b) 0.09 c) 0.27 d) 0.23
20. What is the probability that an American chosen at random has traveled to Canada but not Mexico? a) 0.18 b) 0.09 c) 0.14 d) 0.04
21. Travel to Mexico and travel to Canada are ____________ events. a) Independent b) Disjoint c) Both a and b d) Neither a nor b
22. What is the probability that an American chosen at random has traveled to Mexico, given they have traveled to Canada?
a) 0.04
b) 0.4444
c) 0.2222
d) 0.09
23. The combined weight of these four bags is a random variable with a standard deviation (in oz.) of a) 0.16. b) 0.40. c) 0.64. d) 0.80.
The high temperature in Chicago for the month of August is approximately normally distributed with mean ( = 80( F and standard deviation ( = 8( F. Use this information to answer the next two questions.
24. What is the probability that on any given day in August, the high temperature is above 90°F?
a) 0.0125
a) 0.8944
b) 0.1056
c) 0.0001
25. What is the probability that a random sample of 16 days in August have a sample mean, [pic] high temperature of at least 82( F? a) 0.5987 b) 0.2500 c) 0.1587
Cannot be determined