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Object X's Moon Research Paper

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Our Planet Hunter Team from Lick Observatory possibly found a new planet. We are an observatory owned by the University of California and focus on astronomical observations. This Object X (to be determined as a planet) it does not seem to be a round-shape form, orbits the sun, Object X’s moon is 57,783 kilometers between Object X, Object X’s moon takes 32.17 days to do one full orbit, and crosses Pluto. These factors of Object X have similar factors of an actual planet. The International Astronomical Union (IAU) explains a planet must orbit the sun, has enough mass to be nearly-round shape due to gravity, and has a clear neighborhood around the object’s orbit. Our team will use Kepler’s Third Law (an equation used by using the information …show more content…

Km on both sides cancel out because we are dividing the same unit which leaves 57,783 multiplying to 1000m. This gives us 57,783,000m, but we have to turn it into scientific notation to make calculations easier. There is a decimal point in 57,783,000. and we move it 7 times to the left which automatically becomes 5.778 * 107. The exponent is 7 because we moved the decimal 7 times to the left producing a smaller number and is multiplied by 10 because it is a base (system of decimals). Now we have to convert 32.17 days to seconds.

(32.17days/24hours/ 60minutes /60seconds)/(days/hours/minutes) → s = 2,779,488s or 2.779 * 106

There are twenty four hours in a day, sixty minutes in an hours, and sixty seconds in a minute. We divide to cancel the units leaving us seconds and multiplying all the numbers. The answer in seconds is 2,779,488 seconds, and scientific notation of that is 2.779 * 106. Now that we have our numbers in meters and seconds, we can plug the number in the equation to evaluate the mass of Planet X.
Step 3
M =((4π^2 r^3 ))/(GP^2 ) G = 6.673*〖10〗^(-11) m^3 kg^(-1) s^(-2) r = 5.778*107 P = 2.779 *
…show more content…

We still have to see if Planet X’s mass is enough to be considered a planet, so we have to divide the mass of planet x and the mass of earth which is 5.980 * 1024.
(1.478*〖10〗^22 kg)/(5.980*〖10〗^24 ) = .2472 * 10-2 kg
We divide the numbers and we get .2472 * 10-2. Now we simplify the scientific notation so we end with:
2.472 * 10-3
We multiply this scientific notation to 100 so we can find a percentage of the mass. The Scientific notation will convert to an actual decimal in order to find an accurate percentage of the mass of Planet X.
.002472 * 100 =
.247%

Conclusion
The mass of Planet X is .247% meaning it is less than 1% of mass. This is an unusually small number for a planet. Planet X has similar qualities to a planet, but its mass is too small. Even if Planet X is not a planet, there are many undiscovered planets waiting to be observed. It may seem a waste of time, but we learn new things through every calculation we make for every existent body in the galaxy.

Reference "International Astronomical Union | IAU." International Astronomical Union | IAU. Web. 21 Sept.


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