Principle : Vitamin C is a strong reducing agent. It can decolorize the blue dye DCPIP. The amount of vitamin C in a food sample can be estimated by the amount of it that is used to decolorize a fixed amount of DCPIP.
Apparatus :
Test tube, clean and dry
Test tube rack
5 ml syringe or a good quality squeezing pipette
1 ml pipette pipette filler
Materials :
________% vitamin C solution, (standard for calibration) ; prepared from commercial vitamin C tablet (0.02 %)
________ % DCPIP solution, freshly prepared
Possible samples :
* grape juice, paper pack
● lemon juice, diluted from fresh squash (Citrus fruit) ● orange juice, diluted from fresh squash (Citrus fruit) ● orange juice, diluted from bottled drink Mr. Juicy (Citrus fruit)
* kiwi fruit juice, diluted from fresh squash (non-citrus fruit, but high in vitamin C)
● green pepper extract / juice
Procedure
1. Use a 1 ml pipette and a pipette filler to prepare a test tube with 1 ml of blue DCPIP solution. Prepare a few in a batch.
2. Fill a 5 ml syringe with the standard vitamin C solution. (Or use a dropper)
3. Slowly (gently) add the vitamin C solution into the DCPIP test tube drop by drop. [ Precautions : Hold the dropper vertically. Make sure that the drop size is constant.]
4. After adding one drop, DO NOT shake the contents.
5. Stop dropping when the blue colour disappears. [The end point is taken when the blue solution suddenly becomes colourless.]
6. Record the number of drops of vitamin C solution required to decolourise the DCPIP solution.
7. Repeat the experiment twice (= two times).
8. Enter the results into the table below. [Each student must enter his/her data sheet.]
9. Repeat the experiment for other fruit juices.
10. Rinse the dropper/syringe with water and then a new fruit juice to reduce