Preview

Pdf Chapter 9

Good Essays
Open Document
Open Document
601 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Pdf Chapter 9
Chapter 9 Estimation and Confidence Intervals
30. A random sample of 85 group leaders, supervisors, and similar personnel revealed that a person spent an average 6.5 years on the job before being promoted. The population standard deviation was 1.7 years. Using the 0.95 degree of confidence, what is the confidence interval for the population mean? A) 6.99 and 7.99 B) 4.15 and 7.15 C) 6.14 and 6.86 D) 6.49 and 7.49 Answer: C 31. The mean weight of trucks traveling on a particular section of I-475 is not known. A state highway inspector needs an estimate of the mean. He selects a random sample of 49 trucks passing the weighing station and finds the mean is 15.8 tons. The population standard deviation is 3.8 tons. What is the 95 percent interval
…show more content…

A) 78.2% to 81.8% B) 69.2% to 86.4% C) 76.5% to 83.5% D) 77.7% to 82.3% Answer: A Use the following to answer questions 81-83: A student wanted to quickly construct a 95% confidence interval for the …show more content…

What is the 99% confidence interval for the population mean? A) [17.42, 20.78] B) [17.48, 20.72] C) [14.23, 23.98] D) [0.44, 3.80] Answer: A Use the following to answer questions 84-86: A survey of 25 grocery stores revealed that the average price of a gallon of milk was $2.98 with a standard error of $0.10. 84. What is the 95% confidence interval to estimate the true cost of a gallon of milk? A) $2.81 to $3.15 B) $2.94 to $3.02 C) $2.77 to $3.19 D) $2.95 to $3.01 Answer: C 85. What is the 98% confidence interval to estimate the true cost of a gallon of milk? A) $2.73 to $3.23 B) $2.85 to $3.11 C) $2.94 to $3.02 D) $2.95 to $ 3.01 Answer: A 90. A pharmaceutical company wanted to estimate the population mean of monthly sales for their 250 sales people. Forty sales people were randomly selected. Their mean monthly sales were $10,000 with a standard deviation of $1000. Construct a 95% confidence interval for the population mean. A) [9,690.1, 10,309.9] B) [9,715.5, 10,284.5] C) [8,040, 11,960] D) [8,000, 12,000] Answer: B Use the following to answer questions 91-92: A survey of an urban university (population of 25,450) showed that 750 of 1100 students sampled attended a home football game during the season. What inferences can be made about student attendance at football games? 91. Using the 99% level of confidence, what is the confidence interval? A) [0.767, 0.814] B) [0.0.6550, 0.7050] C) [0.6659, 0.6941] D) [0.0.6795, 0.6805] Answer: C 92. Using the 90% level of

You May Also Find These Documents Helpful

  • Good Essays

    The next step in solving the problem is to construct a 95% confidence interval for the average amount of the company’s 16-ounce bottles. The confidence interval was constructed by drawing a normal distribution with c = 95%, a = 0.050, and Zc = 0.025. The Zc value was entered into the Z◘ (z box) function in the Aleks calculator that resulted in a Z score of +1.96 and -1.96. We calculate the standard error (SE) by dividing the s by the Square root of n which is the sample size. The margin of error is calculated by multiplying the z score = 1.96 by the std. dev. = 0.5503/the square root of n = 5.4772. The result is a 0.020 margin of error. The margin of error is added to and subtracted from the mean to give two numbers the lower and upper values. The lower value is 14.85 and the upper value is 14.89. So, we can say that with 95% confidence the mean of the sample is between 14.85 and 14.89.…

    • 670 Words
    • 3 Pages
    Good Essays
  • Satisfactory Essays

    · Discuss the confidence intervals and their usefulness based on the number of data points.…

    • 468 Words
    • 3 Pages
    Satisfactory Essays
  • Better Essays

    The mean among the sample bottles is 14.87. The calculation to find the mean is to add all the ounces per bottle. The total is 446.1 divided by the random sample of 30. The average ounces in the bottles are less than 16 ounces. The median for the soda bottles is 14.8. The median is imputed by dividing the random number of 30 by 2 which equals 15. Arrange the ounces from smallest to largest, and select the number that falls on 15. This will provide the median for the thirty bottles. The standard deviation for the ounces in the bottles is 0.55. The standard deviation must be known in order to compute the confidence interval. To find the…

    • 1093 Words
    • 5 Pages
    Better Essays
  • Powerful Essays

    Scooter Case Study

    • 910 Words
    • 4 Pages

    i) Construct a 95% confidence interval of what operating income could be after taxes if the customer were to order a total of 60,000 units of TEES and ROOS.…

    • 910 Words
    • 4 Pages
    Powerful Essays
  • Satisfactory Essays

    Tutorial Solution Week9

    • 946 Words
    • 4 Pages

    WEEK 9 TUTORIAL EXERCISES (To be discussed in the week starting May 6) 1. Perform the following hypothesis tests of the population mean. In each case, illustrate the rejection regions on both the Z and…

    • 946 Words
    • 4 Pages
    Satisfactory Essays
  • Satisfactory Essays

    Math 533 Part B

    • 1217 Words
    • 6 Pages

    I will use a = .05 as the significance level, and observing the sample size of n < 30 which tells me I need to use a Z-Test to find the mean of this test and the hypothesis. As the alternative hypothesis is Ha: u < $45,000, the given test is a one-tailed Z-Test.…

    • 1217 Words
    • 6 Pages
    Satisfactory Essays
  • Satisfactory Essays

    workbook 18

    • 321 Words
    • 2 Pages

    3. Assuming that the distribution for General Health Perceptions is normal, 95% of the females’ scores around the mean were between what values? Round your answer to two decimal places.…

    • 321 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Mba510 Week 5 Problem Set

    • 2326 Words
    • 10 Pages

    A processor of carrots cuts the green top off each carrot, washes the carrots, and inserts six to a package. Twenty packages are inserted in a box for shipment. To test the weight of the boxes, a few were checked. The mean weight was 20.4 pounds, the standard deviation 0.5 pounds. How many boxes must the processor sample to be 95 percent confident that the sample mean does not differ from the population mean by more than 0.2 pounds?…

    • 2326 Words
    • 10 Pages
    Good Essays
  • Satisfactory Essays

    A simple random sample of 40 salaries of NCAA football coaches has a mean of $415,953 and a standard deviation of $463,364. Construct a 95% confidence interval estimate of the mean salary of an NCAA football coach.…

    • 388 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    Quiz 3 stats

    • 4016 Words
    • 19 Pages

    Construct a 90% confidence interval estimate for the standard deviation of family dental expenses for all employees of this corporation.…

    • 4016 Words
    • 19 Pages
    Satisfactory Essays
  • Satisfactory Essays

    chapter 9 documents

    • 1182 Words
    • 4 Pages

    The birth of Islam started a fairly new religion and warfare was commonplace. So, the Holy Wars might help to explain the references in the Quran to fighting and warfare. For example, if someone were to threaten Islam and Allah’s teachings, then the Quran gives the authority to Muslims to fight in God’s cause. Fighting and warfare was common in this region during this time frame so it was important for the Quran to establish some guidelines for its followers.…

    • 1182 Words
    • 4 Pages
    Satisfactory Essays
  • Better Essays

    An interval estimate (23.8, 30.6) is determined for the mean age of NSCC students. Identify the point estimate and the margin of error of the interval estimate.…

    • 1241 Words
    • 5 Pages
    Better Essays
  • Better Essays

    Process Improvement Plan

    • 1395 Words
    • 6 Pages

    2). 95% is set as the confidence level for the above data. The sample size is below 15 and the chart below depicts the distribution of average mean for the five weeks being normal (University of Phoenix, 2010, Estimation and Confidence Intervals, p. 305).…

    • 1395 Words
    • 6 Pages
    Better Essays
  • Satisfactory Essays

    Risk Pooling Assignment

    • 356 Words
    • 2 Pages

    4) You will also need to use the critical value for the standard Normal distribution (i.e., z-score) associated with the 95% confidence interval. You can look it up in a z-table in any statistics book or online.…

    • 356 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    econometric solution

    • 264 Words
    • 2 Pages

    The 95% confidence interval for the mean score of all New Jersey third graders is:…

    • 264 Words
    • 2 Pages
    Satisfactory Essays