Pentane Lab Report

By analyzing the data collected in the experiment and subsequently constructing graphs as shown above in figure 5 that plot the change of temperature against time with the inclusion of the different quantities of the isomer of pentane used. There are many kinds of trends which can be speculated about through analyzing the result graphs. Some of the different ways to identify trends within a graph, the main one being trend lines, the r2 value of the graph. A r2 value is a statistical measure of how close the data is related to all of the measurements found and how they fit on the regression line. The closer the r2 value is to the value of 1, the better the data fits on the regression line. Henceforth, if the value is 1 then it means that the
But what was observed is thoroughly contradictory. Compared to the 3mL sample, the 1 mL sample took about 2 minutes longer in reaction time as presented in table 4. According to research and chemical theory, this should not have happened and time should have actually been less than that was obtained in the 3mL experimentations. Furthermore, the results should have also shown decreases in average temp from 3 mL to 1 mL but there was no change in temperature. Hence it was also observed through table 2 that there is an average increase of the temp of the 2 methyl butane by 8.34 C but from table 3, it can be seen that there is a decrease in 2 methyl butane by 7.66 degrees Celsius, which was rather unexpected. However, these results could be looked upon from a different perspective, the side from which the results that were obtained in the 1mL experiment could have been expected. As different concentrations might affect the reaction rate, it would burn slower due to it not having as high flame as compared to 3mL hence taking more time to break those bonds. It was observed through the experiment that the flames for 1 mL n-pentane were higher than 2 methyl butane resulting in a decrease in the temperature from 3 mL. The low flame
The saturated unbranched alkenes will have a much quicker reaction rate but have low enthalpy values as it doesn’t take that much energy to break those bonds. Due to the neo-pentane having the larger density out of the other two isomers of pentane, it will have the lowest enthalpy value but the fastest reaction rate. Meaning that iso-pentane for higher concentrations will have high enthalpy values due to the trends in the graph meaning that it will produce the biggest flames out of the other two isomers of pentane. If the concentration is low such as 0.5 then you would expect for 1mL of n-pentane to produce more heat, hence having a higher heat capacity and a slower reaction rate. Moreover, iso-pentane produces less heat as it takes more time for it to react hence ending in a lower enthalpy value but a faster reaction rate because of its bonds being closer to each other. These assumptions are purely made due to the trends which can be seen in the graph, which is that time is about three times as much as the temperature. All the factors and the data which were collected had some correlation with the structure of the molecule. A conclusion can be made that because the atoms are packed tightly together in a sea of delocalized cat ions, sp hybridize bonds are made.