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Phyc 260 Solutions
Chapter 24
Gauss’s Law

Multiple Choice

1. Two charges of 15 pC and –40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through the surface of the cube.

a. +2.8 N ( m2/C b. –1.1 N ( m2/C c. +1.1 N ( m2/C d. –2.8 N ( m2/C e. –0.47 N ( m2/C

2. The total electric flux through a closed cylindrical (length = 1.2 m, diameter = 0.20 m) surface is equal to –5.0 N ( m2/C. Determine the net charge within the cylinder.

a. –62 pC b. –53 pC c. –44 pC d. –71 pC e. –16 pC

3. Charges q and Q are placed on the x axis at x = 0 and x = 2.0 m, respectively. If q = –40 pC and Q = +30 pC, determine the net flux through a spherical surface (radius = 1.0 m) centered on the origin.

a. –9.6 N ( m2/C b. –6.8 N ( m2/C c. –8.5 N ( m2/C d. –4.5 N ( m2/C e. –1.1 N ( m2/C

4. A uniform linear charge density of 4.0 nC/m is distributed along the entire x axis. Consider a spherical (radius = 5.0 cm) surface centered on the origin. Determine the electric flux through this surface.

a. 68 N ( m2/C b. 62 N ( m2/C c. 45 N ( m2/C d. 79 N ( m2/C e. 23 N ( m2/C

5. A uniform charge density of 500 nC/m3 is distributed throughout a spherical volume (radius = 16 cm). Consider a cubical (4.0 cm along the edge) surface completely inside the sphere. Determine the electric flux through this surface.

a. 7.1 N ( m2/C b. 3.6 N ( m2/C c. 12 N ( m2/C d. 19 N ( m2/C e. 970 N ( m2/C

6. A point charge +Q is located on the x axis at x = a, and a second point charge –Q is located on the x axis at x = –a. A Gaussian surface with radius r = 2a is centered at the origin. The flux through this Gaussian surface is

a. zero because the negative flux over one hemisphere is equal to the positive flux over the other. b. greater than zero. c. zero because at every

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