PROBLEM: A student suggest that there is a proportional relationship between height at which a plasticine sphere is dropped and the diameter of the flattened part after dropping. Design an experiment to determine if this suggestion is true or not.
AIM: To investigate the relationship between the drop height and the flattened part of a plasticine sphere after being dropped.
HYPOTHESIS: As the height of the sphere plasticine increases the diameter increases.
VARIABLES:
Manipulating: The drop height of the sphere plasticine
Responding: The diameter of the flattened part of the sphere.
Controlled: The size of the ball, the surface area of the drop height and the material from which the sphere is made.
APPARATUS: Sphere plasticine, meter ruler, Vernier caliper, string, marker
METHOD:
Make a sphere out of plasticine and measure its size using the Vernier caliper to maintain a constant size throughout the experiment.
Get a flat and smooth surface area.
Use a meter ruler to measure 60m above the surface area and hold the plasticine to the ruler at the 60m and drop it.
Wrap a piece of string around the flattened part of the sphere and use a marker to mark off where the string stops. Measure the length of the string up to where the mark stops using a meter ruler. Divide the length of the string by 3.14 (pi) to get the diameter.
Record the drop height and the diameter of the sphere in a table.
Roll the plasticine back into a sphere using the measurements from the Vernier caliper.
Measure 40m above the surface area using a meter ruler and hold the plasticine to the ruler and drop it from that height.
Wrap a piece of string around the flattened part of the sphere and use a marker to mark off where the string stops. Measure the length of the string up to where the mark stops using a meter ruler. Divide the length of the string by 3.14 (pi) to get the diameter.
Record the drop