Preparation of the NaOH Solution

Preparation of the NaOH Solution
Mass of NaOH before standing = NaOH before standing (g) – beaker (g) = 111.490 g – 110.970 g = 0.520 g
Mass of NaOH after standing = NaOH after standing (g) – beaker (g) = 111.500 g – 110.970 g = 0.530 g
Standardization of the NaOH solution
TRIAL I
Volume of NaOH solution = Final reading of buret - Initial reading of buret = 13.80 mL – 0.00 mL = 13.80 mL
Converting the Volume (mL) to Volume (L) Volume (liters) = Volume (mL) x = 13.80 mL x = 0.01380 L
Moles of potassium acid phthalate = = = 0.000735
Moles of NaOH solution = Moles of (HKC8H4O4) x = 0.000735 mol x = 0.000735 mol
Molarity (NaOH) = = = 0.053 M
TRIAL II
Volume of NaOH solution = Final reading of buret - Initial reading of buret =27.20 mL– 13.80 mL = 13.40 mL
Converting the Volume (mL) to Volume (L) Volume (liters) = Volume (mL) x = 13.40 mL x = 0.01340 L
Moles of potassium acid phthalate = = = 0.000735
Moles of NaOH = Moles of (HKC8H4O4) x = 0.000735 mol x = 0.000735 mol
Molarity (NaOH) = = = 0.055 M

Average Molarity (NaOH) = = = 0.54 M
Titration of Soft drink samples with NaOH solution
Soft drink sample 1 TRIAL I
Volume of NaOH used (mL) = Final reading of buret - Initial reading of buret = 7.20 mL – 0.00 mL = 7.20 mL
Moles of NaOH = Molarity x Volume (NaOH) = (0.054 mol/L) (7.20/1000) L = 0.003888 L or 3.89x10-4 L
Soft drink sample 1 TRIAL II
Volume of NaOH used (mL) = Final reading of buret - Initial reading of buret = 7.70 mL – 0.00 mL = 7.70 mL
Moles of NaOH = Molarity x Volume (NaOH) = (0.054 mol/L) (7.70/1000) L = 0.004158 L or 4.16x10-4 L
Soft drink sample 2 TRIAL I
Volume of NaOH used (mL) = Final reading of buret - Initial reading of buret = 18.40 mL– 7.20 mL = 11.20 mL
Moles of NaOH = Molarity x Volume (NaOH) = (0.054