Table of Contents No | Questions and chapter | | 1 | Apply it 19 - Chapter 3 | | 2 | Apply it 16 - Chapter 4 | | 3 | Apply it 10 - Chapter 10 | | 4 | Apply it 3 - Chapter 11 | | 5 | Apply it 5 - Chapter 12 | | 6 | Problems 17.7.11 - Chapter 17 | |
Chapter 3
Apply it 19. A coffee shop specialises in blending gourmet coffees. From type A, type B, and type C coffees, the owner wants to prepare a blend that will sell for $8.50 for a 1-pound bag. The cost per pound of these coffees is $12, $9, and $7, respectively. The amount of type B is to be twice the amount of type A. How much of each type of coffee will be in the final blend?
Answer :
We know that: A+B+C=1 B=2A 1 =3A+C A=(1-C)3
From the question: 12A+9B+7C=8.50 Putting 2A in place of B: 12A+18A+7C=8.50 30A+7C=8.50 30(1-C)3+ 7C=8.50 10-10C+7C=8.50 Therefore, C=0.5 3A+C=1 Substitute in 3A+C=1
3A+ 0.5=1 Therefore, A=16 B=2A Substitute in (1)
B=216= 13
Chapter 4
Apply it 16. Greg took a number and multiplied it by a power of 32. Jean started with the same number and got the same result when she multiplied it by 4 raised to a number that was nine less than three times the exponent that Greg used. What power of 32 did Greg use ?
Answer :
Let the number slected by boht be 1 let the power of 32 be y
So: 32^y=4^(3y-9)