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Ramp Experiment

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Ramp Experiment
Purpose: To find the initial velocity of a marble leaving a ramp using time, range, and background information learned in class.

Equipment: The equipment used in this experiment was a toy track and ramp, a small marble, multiple Physics textbooks, meter sticks, bright-colored cardstock, masking tape, sidewalk chalk, plastic bag and a cloth.

Procedure:
Our experimental values include the height that the marble would travel, y= 88.1 cm, and our ramp angle, θ= 44.0°. These independent variables were best controlled using tape to hold our equipment in place.
First, all of the necessary equipment was collected and set up. Textbooks of the same kind (for example, four Giancoli Physics textbooks edition six) were stacked near the middle of the table, and the ramp was taped flush with the edge of the table. A car track was connected to the ramp and was held up by the stack of books. Measurements were recorded regarding book height, ramp
…show more content…
After each trial, a soft cloth was used to remove the chalk residue from the car track to best reduce any error that the chalk dust may cause, such as adding more friction.

Data:
The recorded data required needs to be range, or the distance the marble landed from the table, and the time taken from first rolling to landing on the cardstock. The amount of trials recorded should be equal to or more than ten.

Data Analysis: In order to find the initial velocity, the horizontal and vertical components need to be calculated first using the average time, range and height Δy= 82.8cm (table height) + 5.35cm (ramp height) = 88.1cm = 0.881m
Finding the initial vertical velocity using: y= vy0t + 0.5gt2 0.881m = 0.88v + (-4.90m/s/s)(0.88s)2 0.881 = 0.88v + -3.79 4.68 = 0.88v vy0 = 5.3m/s
Finding the initial horizontal velocity using: x= vx0t 0.3724m = 0.88v vx0 = 0.42m/s
Solving for the resultant vector from the components using: v02 = vx2 + vy2 v0 = 0.42m/s2+ 5.3m/s2 = 28.3=

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