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Separating Selected Metal Cations by Paper Chromatography

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Separating Selected Metal Cations by Paper Chromatography
Chemistry 266
Dominick Armstrong

10/10/2012

Acid-Base Titration
Introduction

Acid and bases are two important classes of compounds that react to form a salt and water. When mixing acids and bases a precise amount of the base must be added in order to reach the equivalence point. At this point, one reactant has been exactly consumed by the addition of the other reactant. When performing chemical reactions chemist use a process called titration to determine the equivalence point of the reaction. Once the equivalence point is known then chemist can correctly determine the amount the concentration of the acid and the base.
In this experiment acid-base titration will be used to determine the concentration of HCl at equilibrium when it reacts with the NaOH H+ (aq)+ Cl- (aq) + Na+ (aq) + OH- →H2O(l) + Na+ (aq)+ Cl- (aq)

Procedure

When performing this experiment one must first obtain and wear goggles. Next add 40mL of distilled water to a 100mL beaker, then add 5.00mL of HCl to the beaker.Then obtain 40mL of 0.1M NaOH. Place the NaOH in a 60mL reagent reservoir and drain a small amount into a 250mL beaker to fill the tip. Connect the Ph sensor to the LabQuest and set up the drop counter.Then calibrate the titrant by adjusting the reservoir tip to and letting the NaOH slowly drain into a graduated cylinder until 9 or 1o ml has been recorded. After the LabQuest has been calibrated discard the solution. The assemble the titration apparatus as shown in the picture below.

Place the HCl solution onto the magnetic stirrer and slowly titrate the NaOH into the solution. Start the data collection to calculate the volume of NaOH is added when the solution reaches its equivalence point. Then right down the calculations and disassemble the apparatus.

Discussion

My lab group and I completed this experiment doing two trials. We found that both trials were concluded with similar results. In trial 1 we found that the volume of

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