Slope of BC = (0 - 2)/(-3 - 3) = 1/3
Slope of CD (-1 - 2)/(4 - 3) = -3
Slope of AD =(-3 + 1)/(-2 - 4) = 1/3
I verified this as a parallelogram. Now I must figure out if this is a rhombus by seeing if adjacent sides are equal.
Distance of AB = √[(-2 + 3)^2 + (-3 - 0)^2] = √10
Distance of BC = √[(-3 - 3)^2 + (0 - 2)^2] = 2√10
Although one side is simply just twice as long as the other, these adjacent sides are not congruent, and therefore this parallelogram is not a rhombus. This is also not a square then, because all squares are rhombuses.
Now figure out if this parallelogram is a rectangle by seeing if these sides meet perpendicularly to each other. This can be easily found out when making