Soutwestern Term Project 1 
Chapter 3
SOUTHWESTERN UNIVERSITY: A
DisQ - 1)
Activity Mean
S.D.
Variance
T.a=30
3.33
11.11
T.b=60
10.00
100.00
T.c=65
8.33
69.39
T.d=55
11.66
136.10
T.e=30
1.67
2.78
T.f=0
0.10
0.00
T.g=30
1.67
2.78
T.h=20
3.33
11.11
T.i=30
6.67
44.44
T.j=10
0.67
0.44
T.k=0
0.10
0.00
T.l=30
6.67
44.44
Critical Path= A-C-D-G-H-I-L (260 Days)
Variance of critical path = 11.11 + 136.1 + 2.78 + 11.11 + 44.44 + 44.44 + = 319.37
S.D of critical path=17.87 days
DisQ - 2)
P(t< or = 270)
P(Z< or = (270-260/17.87))=P(Z< or = 0.56) = 0.712 = 71.2%
DisQ - 3)
Activity
Normal time (days)
Crash Time (days)
Crash cost/Day
A
30
20
$1,500
B
60
20
$3,500
C
65
50
$4,000
D
55
30
$1,900
E
30
25
$9,500
F
0
0
$0
G
30
25
$2,500
H
20
10
$2,000
I
30
20
$2,000
J
10
8
$6,000
K
0
0
$0
L
30
20
$4,500
The total amount that it will take for them to crash to 240 days will be $34,000 additionally to to there original price.
Chapter 4
SOUTHWESTERN UNIVERSITY: B
DisQ – 1)
We can approach this with the method of separate forecasts models for each individual game. In this situation we can clearly see that 2 games stand out in attendance then the rest. Which is the homecoming game and the fourth game of the season.
Game
Model
2006 Forecast
2007 Forecast
R prime
1
Y=30,713+2,534x
48,453
50,988
0.92
2
Y=37,640+2,146x
52,660
54,806
0.90
3
Y=36,940+1,560x
47,860
49,420
0.91
4
Y=22,567+2,143x
37,567
39,710
0.88
5
Y=30,440+3,146x
52,460
55,606
0.93
total
239,000
250,530
Y = attendance x = time
1) We can say that the revenue that can be expected in 2006=(239,000 x 20)= $4,780,000
In 2007= (250,530 x 21) = $5,261,130
2) As seen by the results in the calculations a few of the games that are being predicted attendance have an over the maximum for attendance. I would recommend expanding the stadium or build a new one.
Chapter 6
SOUTHWESTERN UNIVERSITY: C
1. There are lots of ways to analyze this data. We suggest getting the student to begin by considering the tools of TQM and go from there. Here we
SOUTHWESTERN UNIVERSITY: A
DisQ - 1)
Activity Mean
S.D.
Variance
T.a=30
3.33
11.11
T.b=60
10.00
100.00
T.c=65
8.33
69.39
T.d=55
11.66
136.10
T.e=30
1.67
2.78
T.f=0
0.10
0.00
T.g=30
1.67
2.78
T.h=20
3.33
11.11
T.i=30
6.67
44.44
T.j=10
0.67
0.44
T.k=0
0.10
0.00
T.l=30
6.67
44.44
Critical Path= A-C-D-G-H-I-L (260 Days)
Variance of critical path = 11.11 + 136.1 + 2.78 + 11.11 + 44.44 + 44.44 + = 319.37
S.D of critical path=17.87 days
DisQ - 2)
P(t< or = 270)
P(Z< or = (270-260/17.87))=P(Z< or = 0.56) = 0.712 = 71.2%
DisQ - 3)
Activity
Normal time (days)
Crash Time (days)
Crash cost/Day
A
30
20
$1,500
B
60
20
$3,500
C
65
50
$4,000
D
55
30
$1,900
E
30
25
$9,500
F
0
0
$0
G
30
25
$2,500
H
20
10
$2,000
I
30
20
$2,000
J
10
8
$6,000
K
0
0
$0
L
30
20
$4,500
The total amount that it will take for them to crash to 240 days will be $34,000 additionally to to there original price.
Chapter 4
SOUTHWESTERN UNIVERSITY: B
DisQ – 1)
We can approach this with the method of separate forecasts models for each individual game. In this situation we can clearly see that 2 games stand out in attendance then the rest. Which is the homecoming game and the fourth game of the season.
Game
Model
2006 Forecast
2007 Forecast
R prime
1
Y=30,713+2,534x
48,453
50,988
0.92
2
Y=37,640+2,146x
52,660
54,806
0.90
3
Y=36,940+1,560x
47,860
49,420
0.91
4
Y=22,567+2,143x
37,567
39,710
0.88
5
Y=30,440+3,146x
52,460
55,606
0.93
total
239,000
250,530
Y = attendance x = time
1) We can say that the revenue that can be expected in 2006=(239,000 x 20)= $4,780,000
In 2007= (250,530 x 21) = $5,261,130
2) As seen by the results in the calculations a few of the games that are being predicted attendance have an over the maximum for attendance. I would recommend expanding the stadium or build a new one.
Chapter 6
SOUTHWESTERN UNIVERSITY: C
1. There are lots of ways to analyze this data. We suggest getting the student to begin by considering the tools of TQM and go from there. Here we