Preview

Stiochiometry of a Precipitaiton Reaction

Powerful Essays
Open Document
Open Document
597 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Stiochiometry of a Precipitaiton Reaction
Abstract: The objective of this lab is to calculate the theoretical, actual, and percent yield of the product from a precipitation reaction. It is also to learn concepts of solubility and the formation of a precipitate.
The Experiment and Observation: Weigh out your 1.0g of CaCl2-2H20 and put it into the 100mL beaker, add your 25mL of distilled water and stir to form the calcium chloride solution. Next, use stoichiometry to determine how much Na2CO3 and put it into a small paper cup. Then add the 25mL of distilled water to make the sodium carbonate solution. Mix the two solutions in the beaker and a precipitate of calcium carbonate will form instantly. Next, set up your filtration assembly. After the filtration assembly is ready, swirl the contents of the beaker to dislodge any precipitate from the sides. Then, pour the content of the beaker into the filter paper-lined funnel carefully. Afterwards you will need to measure out 2 to 5mL of distilled water into a graduated cylinder. Pour it down the sides of the beaker, swirl, and pour into the filter paper-lined funnel. Once all the liquid has drained from the funnel, lay the filter paper containing the precipitate on folded layers of paper towels and set it somewhere to air-dry. Once the filter paper and the precipitated calcium carbonate are completely dry, weigh them, subtract the original weight of the empty filter paper, and record the net weight of the calcium carbonate. That is your actual yield of calcium carbonate. Then, you can calculate the percent yield, using your theoretical yield and actual yield. Be sure to clean up properly, rinse any remaining chemicals down the sink and throw paper cups and towels in the garbage. Clean and dry all equipment you used. The following results will be observed:
1g CaCl*2H₂O*(1moleCaCl₂*2H₂O/147g CaCl*2H₂O)*(1mol Na₂CO₃/1mol CaCl₂*2H₂O)*160g Na₂CO₃/1mo lNa₂CO₃= 1g of CaCl₂*2H₂O and .72 Na₂CO₃
Which will provide a Ca CO₃ Theoretical yield as :
1 g CaCl2•2H2O x 1

You May Also Find These Documents Helpful

  • Good Essays

    Testing the actual yield versus the theoretical yield of NaCl when HCl is titrated into Na2CO3 and NaHCO3. When 0.15g of both NaHCO3 and Na2CO3 are titrated with HCl, then 0.165g of NaCl should form from the NaHCO3, and 0.104g of NaCl should form from the 0.15g of Na2CO3.…

    • 420 Words
    • 2 Pages
    Good Essays
  • Good Essays

    a. If you did not wash all of the Calcium Carbonate out of the beaker and into the filter during step 5, would your percent yield be larger or smaller?…

    • 483 Words
    • 2 Pages
    Good Essays
  • Good Essays

    6.03 Calorimetry Lab

    • 446 Words
    • 2 Pages

    In this lab, we dissolved a calcium-enriched tablet and participate the calcium ion as calcium carbonate. Our purpose is to determine the masses of calcium carbonate and calcium ion, to determine the mass percent of calcium ion in the tablet and to compare the masses and the percent with the listed tablet ingredients. This time we used a 150mL beaker, analytical balance, forceps, a 50mL graduated cylinder, a glass rod, beaker tongs, a hot plate, two 16 x 125-mm test tubes, centrifuge, a medicine dropper, a filter paper, a filter funnel, a 250-mL Erlenmeyer flask, a watch glass, a drying oven, a spatula and a red litmus paper. The chemicals we need were 20mL of 2.0M HCl, a calcium-enriched tablet and 25mL of 1.0M Na2CO3 solution.…

    • 446 Words
    • 2 Pages
    Good Essays
  • Good Essays

    Experiment 9 okiemute

    • 589 Words
    • 3 Pages

    Initially it was calculated that 0.68 g of CaCO3 was needed for a full reaction. The net mass of Na2CO3 (reactant) was 0.72 g and the net mass of CaCO3 was 0.5 g. I was able to use the graduated cylinder to measure the 25ml of distilled water, before pouring it into the beak and inside the beaker was a 1.0g of…

    • 589 Words
    • 3 Pages
    Good Essays
  • Powerful Essays

    D1 Karan 4444

    • 1403 Words
    • 4 Pages

    When making a standard solution anywhere even if it is in a lab or an industry it is important that you have the right type of PPE equipment (personal protective equipment). You will need a lab coat and goggles disposal gloves can also be used but they are not really as necessary as the other two. The first step in making a standard solution in a lab is by putting the weighing boat on a weighting scale and pressing the tare button which will set it to zero. This is done so that when you’re measuring the substance in this case sodium carbonate the beakers mass will not be calculated along with the substance so that you can get the accurate value. After you finish that it is important that when you are putting your substance into the weighing boat that you take it off the weighing boat because sodium carbonate is powder and it is very easy for powder to fall and if it falls while you were putting it into your beaker while it was on the weighting in scale it could change your results and you would have to start again. After you have carefully weighed up the amount of the required substance transfer it into a beaker and them use distilled water to rinse the weighing boat as some particle could have been left inside and add that into the beaker as well. After…

    • 1403 Words
    • 4 Pages
    Powerful Essays
  • Better Essays

    First the student will take the weight of a clean dry beaker and record the data. Next ass .15g of the first unknown substance. From there, the student will add 50ml of water to the beaker then dissolve the .15g of the first unknown substance into the water. Once the substance has dissolved, the student will add 10 drops of bromocresol (indicator) into the beaker. After the student will fill the buret all the way up with HCl. Once that is done, begin titration. The HCl should be added into the beaker until the indicator turns green. After it turns green the student will then place it on a hot plate and heat it till the CO2 evaporates and it turns blue again. After that let it cool. Once the substance is cooled. The student will then titrate once more till it turns yellow. The yellow color indicates that the substance has stabilized. Once the substance is fully titrated, the student will place the beaker back on to the hot plate and let all of the water evaporate out of the beaker till there is only the salt (unknown substance) left. Lastly, the student will then measure the weight of the beaker with the salt in it and record the data. Once the data has been obtained the student will subtract the weight of the beaker from the weight of the salt. That calculation will then be used to find the…

    • 1238 Words
    • 4 Pages
    Better Essays
  • Powerful Essays

    Conclusion: The objective of the experiment is to predict the amount of product produced in a precipitation reaction using stoichiometry. Secondly, the experiment accurately measures the reactants and products of a reaction. Also, the experiment is to determine actual yield vs. theoretical yield and to calculate the percent yield. For example in this experiment, we were able to predict that we need 0.72g of Na-2CO3 to fully react with 1g of CaCl2-.2H2O. Another example is that, we calculate the amount of…

    • 567 Words
    • 3 Pages
    Powerful Essays
  • Good Essays

    precipitation reaction will be studied. Stoichiometry will then be used to investigate the amounts of reactants…

    • 1310 Words
    • 6 Pages
    Good Essays
  • Good Essays

    The mass of the weighing dish was measured as 0.6 g. The mass of the filter paper was measured as 1.0 g. Initially it was calculated that 0.68 g of CaCO3 was needed for a full reaction. The net mass of Na2CO3 (reactant) was 0.72 g and the net mass of CaCO3 was 0.7 g. The dried calcium carbonate measured at 0.7 g (net mass).…

    • 578 Words
    • 3 Pages
    Good Essays
  • Good Essays

    A Paper

    • 1140 Words
    • 5 Pages

    The precipitated calcium carbonate is then filtered, dried, and weighed. The moles of calcium carbonate, CaCO3, are equal to the moles of Group 1 metal carbonate, M2CO3, added to the original solution. Dividing the mass of the unknown carbonate by the moles of calcium carbonate yields the formula weight, and thus the identity, of the Group 1 metal carbonate.…

    • 1140 Words
    • 5 Pages
    Good Essays
  • Satisfactory Essays

    4) Place a small piece of Calcium Carbide (CaC2) into the 1000 mL beaker. As it reacts with the water, it will form acetylene gas (C­­2H2). Place thumb over the 1st test tube and invert it into the 1000 mL beaker. When it is below…

    • 334 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    The purpose of this experiment is to examine the percent yield of a precipitate in a double displacement reaction. A solution of calcium citrate and sodium carbonate were mixed together, then the products were filtered out as so only the precipitate remained. The filtered paper was then dried and the mass of the precipitate in the experiment divided by the theoretical mass of the precipitate from the calculated gave the percent yield. The percent yield that was acquired is about 69.1%.…

    • 1338 Words
    • 6 Pages
    Good Essays
  • Powerful Essays

    The objective of this experiment was to synthesize 2.00 grams of CaCo2 for a hypothetical manufacturing company using the two least detrimental (in regards to health and the environment) and least expensive chemicals possible through a precipitate reaction. A precipitate reaction happens when cations and anions of certain aqueous solutions react and combine forming a precipitate, which is an insoluble ionic solid. In this precipitate reaction we dissolved both chosen chemicals (powder Calcium Chloride dihydrate and powder Sodium Carbonate) in distilled water and then mixed them together in a single beaker. Finally we filtered this mixture and let all the water evaporate leaving behind solely the precipitate. In order to determine the amounts needed of each reactant we had to use stoichiometry. First we had to set up a balanced equation of the precipitate reaction that yielded 2.00 grams of CaCo3, then we looked at the ratio of moles reactant to moles product. We then substituted the ratio of the molar mass of each reactant to molar mass of the product in for each mole. We divided this to find out how many grams of reactant for every one gram of product, and finally multiplied this by two. Our final results were lower than the desired 2.00 grams.…

    • 1437 Words
    • 6 Pages
    Powerful Essays
  • Satisfactory Essays

    Stoichiometry Lab Report

    • 2315 Words
    • 10 Pages

    2) According to the equation above, xg NaHCO3 X (1mol NaHCO3/84.01g NaHCO3) X (1mol Na2CO3/2mol NaHCO3) X (105.99g Na2CO3/1mol Na2CO3) + (2.00g – xg NaHCO3) = 1.605g –(a)…

    • 2315 Words
    • 10 Pages
    Satisfactory Essays
  • Good Essays

    eggshell experiment

    • 1266 Words
    • 6 Pages

    accurate measurements of the amount of HCl that did not react with the calcium carbonate.…

    • 1266 Words
    • 6 Pages
    Good Essays