Stoichiometry Design Experiment
Percentage Yield of Calcium Carbonate and HCl
I. Background Information
When marble chips and hydrochloric acid are added together, they form sodium chloride, water, and carbon dioxide. This reaction can be displayed by the balanced equation below;
CaCO3 (s) + HCl (l) NaCl(s) + H2O(l) + CO2 (g) As the carbon dioxide is formed, it will leave the open beaker as a gas. This will result in a loss of mass. The mass change can then be used to find the percentage yield of the reaction. II. Aim
The aim of this experiment is to observe and calculate the percentage yield by studying the mass of yields before and after the reaction. III. Hypothesis
My assumption is that the theoretical yield will be supplementary than actual yield and so the percentage yield will be about 90%. IV. Materials
1. 5 grams of solid CaCO3 2. 20 ml of 1 M HCl 3. 50 cm3 beaker 4. Crucible 5. Electronic Balance
V. Method
1. Weigh the crucible on the balance and record 2. Add 5 grams of CaCO3 and weigh the crucible again to make sure. Record up to 3 significant figures. 3. Pour 20 ml of 1M HCl into the beaker 4. Weigh the beaker with the HCl and record the mass. 5. Carefully add the marble chips and gently stir until all the CaCO3 is dissolved 6. Weigh the beaker again and record the mass.
VI. Results and Calculations
7. Find the limiting reagent 8. Find the theoretical yield by multiplying the amount of moles of the limiting reactant to the molar ration of limiting reactant : ratio and by the molecular weight of the product. 9. Find the percentage yield -->
Pecentage