Preview

Surface Area to Volume Ratio and the Relation to the Rate of Diffusion.

Powerful Essays
Open Document
Open Document
1322 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Surface Area to Volume Ratio and the Relation to the Rate of Diffusion.
Surface Area to Volume Ratio and the Relation to the Rate of Diffusion

Aim and Background

This is an experiment to examine how the Surface Area / Volume Ratio affects the rate of diffusion and how this relates to the size and shape of living organisms.

The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen to diffuse into the cell quickly and allow waste to diffuse out of the cell quickly. If the cells were any bigger than this then it would take too long for the nutrients and oxygen to diffuse into the cell so the cell would probably not survive.

Single celled organisms can survive as they have a large enough surface area to allow all the oxygen and nutrients they need to diffuse through. Larger multi-celled organisms need organs to respire such as lungs or gills.

Method

The reason I chose to do this particular experiment is because I found it very interesting and also because the aim, method, results- basically the whole experiment would be easily understood by the average person who knew nothing about Surface Area/Volume Ratio. The variable being tested in this experiment is the rate of diffusion in relation to the size of the gelatin cube. Another experiment one could do to determine the surface area to volume ratio is to construct a set of cubes out of construction paper- 1 x 1, 2 x 2, 3 x 3 and 4 x 4 (cm).Then use this formula to determine the surface area- L x W x 6 and compare it with the volumes. The formula to determine volumes of cubes is L x W x H. Although that type of experiment will show no insight into SA/V ratio in relation to the rate of diffusion.

Equipment

1. Agar-phenolphthalein - sodium hydroxide jelly

2. O.1 M hydrochloric acid

3. Ruler (cm and mm)

4. Razor blade

5. Paper towel

6. Beaker

Method

1. A block of gelatin which has been dyed

You May Also Find These Documents Helpful

  • Powerful Essays

    Nt1310 Unit 1 Assignment

    • 3643 Words
    • 15 Pages

    The size of the surface must also be large enough to allow sufficient molecules to be transported to accommodate the metabolic processes in cell. For this reason, the surface area to volume ratio for any cell is critical. Size is also important in terms of width and length of a surface carrying out transport of materials. For example; the surface area of single-called alveoli in a person’s lungs, if spread out flat on a surface, would total the area of a football pitch.…

    • 3643 Words
    • 15 Pages
    Powerful Essays
  • Powerful Essays

    BIO 104 Chapter 3

    • 7229 Words
    • 29 Pages

    Different cells have different structures and functions. Diatoms: single-cell eukaryotes Amoeba (a protozoan): a single-cell eukaryote Bacteria: single-cell prokaryotes Molds (fungi): single and multicellular eukaryotic cells Elodea (an aquatic plant): a multicellular eukaryote Humans (these are heart cells): multicellular eukaryotes CELL MEMBRANE…

    • 7229 Words
    • 29 Pages
    Powerful Essays
  • Good Essays

    Rio Biology Quiz Key

    • 4104 Words
    • 17 Pages

    A small cell has a larger surface area-to-volume ratio than a large cell. 7. Rough ER 8. produce proteins. 9.…

    • 4104 Words
    • 17 Pages
    Good Essays
  • Satisfactory Essays

    Lab Report

    • 597 Words
    • 3 Pages

    The purpose of this experiment is to see whether or not temperature plays a role in the percent change during diffusion or osmosis.…

    • 597 Words
    • 3 Pages
    Satisfactory Essays
  • Satisfactory Essays

    Gummy Bear Experiment

    • 331 Words
    • 2 Pages

    After we took that gummy bear out of the water the size of it had changed dramatically the thickness was 25mm the width was 18mm the height was 41mm and the final volume was 18450 mm 3 and that final mass was 13.28grams. Overall we could tell that there was a lot of osmosis and diffusion happening to the gummy bear. If we were to make this experiment better I would suggest leaving the gummy bear in water till it was fully diffused. Another way we could make this experiment better would be to use more expensive gummy bears so that they would not fall apart so easily. Overall I liked the experiment and thought that we got good data it was also fun seeing how much diffusion accord with our own eyes not just the smell of it…

    • 331 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Lab2

    • 520 Words
    • 3 Pages

    How did the surface area affect the diffusion of the cube? What about the volume? What about the surface area to volume ratio? Which…

    • 520 Words
    • 3 Pages
    Good Essays
  • Good Essays

    Aim- To investigate the relationship between the shape of an object and the time taken for a substance to diffuse to its centre.…

    • 701 Words
    • 3 Pages
    Good Essays
  • Better Essays

    This experiment gave a visual understanding of osmosis and diffusion. The first experiment proved that solutes would move down a concentration gradient if permeable to the selective membrane. The second experiment proved different solute concentrations affect the movement of water, depending on the solute concentration inside the cell. The purpose of this lab was to look for different solutes that can cross an artificial membrane and to observe the effect of different concentrations of sucrose on the mass of a potato cell. Results for Part One suggested that the molecular weight of albumin and starch was too large to pass through the dialysis tube, but glucose and sodium sulfate molecules were small enough to pass through the dialysis tube. Also, a decrease in water weight occurred due the dialysis tube being placed in a hypertonic solution. Results for Par Two showed the potato cell having a molar concentration of 0.2734, which caused sucrose concentrations above 0.2 M to have a decrease in mass. Inversely, sucrose concentrations below 0.2 M caused an increase in mass.…

    • 2179 Words
    • 9 Pages
    Better Essays
  • Satisfactory Essays

    Cells are not larger that 1000 um because of the structure of a cell it wouldn’t be possible to make a large ball of thickly solute fluid out of a skin of fatty membrane. The cytoskeleton is built to just take on a certain amount of space size wise, it could fall apart. In addition. Genes and hormones tell how a cell is made, the factors serve to regulate the cell size and prevent its rapid and undifferentiated growth. For example, cancer is what happens when a cell keeps growing. Genes are so smart that they make the codes for cells and its job is to make the codes that keep the cell functioning. Genes evolved to find the best cell size that would give the best size, energy, and structural features for a…

    • 360 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    In this green chemistry experiment of 5,10,15,20-tetraphenylporphyrin was synthesized from benzaldehyde and pyrrole. using microwave irradiation to heat the reactants., The liquid reactants are absorbed on a solid support, silica gel, which acts as a Lewis acid catalyst to facilitate the reaction. The reaction forms a porphyrinogen, which is then oxidized to the porphyrin product by atmospheric oxygen. Column chromatography is performed for the isolation and purification of tetraphenlyporphin, and the thin layer chromatography for analysis.It was concluded that the renention factor(Rf) of the 5,10,15,20- Tetraphenylporphyrin with a percent yield of 61%…

    • 670 Words
    • 3 Pages
    Good Essays
  • Best Essays

    Biology Eei

    • 3499 Words
    • 14 Pages

    The aim of this experiment was to test the effect of surface area on osmosis and the effect of solute concentration on osmosis. To test this aim to hypotheses were devised. 1) If potato pieces are immersed in various salt solutions, then the pieces with the greatest surface area to volume ratio will experience the greatest weight change, because more water can move by osmosis across the potato cell’s semi permeable membrane. 2) If potato pieces are immersed in various salt solutions, then the pieces immersed in the most concentrated solution will experience he greatest weight change, because more water must pass across the potato cells semi permeable membrane by osmosis to achieve an equilibrium. The results from testing these hypotheses did not support either and were shown to be flawed because they did not reflect the theories of osmosis relating to surface area to volume ration and salt concentration.…

    • 3499 Words
    • 14 Pages
    Best Essays
  • Good Essays

    Gas and Solute Exchange

    • 448 Words
    • 2 Pages

    Large surface area: a larger surface area means that more diffusion can occur at once.…

    • 448 Words
    • 2 Pages
    Good Essays
  • Good Essays

    Topic 2 study guide

    • 1769 Words
    • 8 Pages

    2.1.6: Explain the importance of surface area to volume ratio as a factor limiting cell size.…

    • 1769 Words
    • 8 Pages
    Good Essays
  • Satisfactory Essays

    Cell Life

    • 510 Words
    • 3 Pages

    2. Explain the relationship between the rate of diffusion and the size of the solute. What do you think changes in temperature such as cold/hot would have on the diffusion rate?…

    • 510 Words
    • 3 Pages
    Satisfactory Essays
  • Good Essays

    Osmosis And Diffusion

    • 942 Words
    • 4 Pages

    To test diffusion in a liquid, take two flasks and set them at different temperatures. To accomplish the temperature difference, one flask can be placed on ice and one should be left at room temperature. The flask should be placed on ice for about fifteen minutes until the water temperature is equal to the ice bath temperature. To indicate the rate of diffusion one milliliter of dye solution can be placed in each flask. Over period of one hour the colder flask will result in slower diffusion that the flask at room temperate. This experiment accurately supports that at higher temperatures molecules will diffuse faster. Diffusion in a gas can be tested by spraying a scent. However long it takes a person to smell the scent is the diffusion rate. Diffusion rate is measured in meters per second. A factor that may affect diffusion in a gas is a vent causing turbulence which may affect the rate at which the molecules…

    • 942 Words
    • 4 Pages
    Good Essays