The velocity at 0 seconds on the velocity time graph is 14.6 cm/s [down ramp]. The velocity …show more content…
The numbers should be equal as both of them were calculating the instantaneous velocity of the same motion as the same second in time. The values are the exact same, and have a percent difference of 0%, showing that the data gathered using calculations is accurate to the value measured in the observation table.
% Difference = Difference between the values x 100% Average of values = 22 - 22 x 100% 22 = 0 x 100% 22 = …show more content…
Firstly, when the dots on the ticker tape were measured using a measuring stick, the last significant digit was estimated. If the estimations were done incorrectly, the velocity that was calculated could be inaccurate. To improve this, the car could have been rolled down the ramp three times and the average of those measurements could have been used for a more accurate result to measure the change in position. However, if only the increase in velocity and acceleration are calculated, another set of dots that were marked on the ticker tape could have been used as well for trials. A more precise measuring tool could have been used so the measurements would have been much more precise. Other random errors could have been created when the measurements were added onto the graphs. The placement of some points was estimated, and if they were estimated incorrectly, the line and the curve of best of both the distance time and velocity time graph could have been altered. This would have resulted in a different acceleration and average velocity value. To reduce this type of error, the graph could be done on paper that was much more precise, so there is less room for