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Trigonometric Functions and Exact Value

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Trigonometric Functions and Exact Value
Trigonometric Identities

I. Pythagorean Identities A. [pic] B. [pic] C. [pic]

II. Sum and Difference of Angles Identities A. [pic] B. [pic] C. [pic] D. [pic] E. [pic] F. [pic]

III. Double Angle Identities A. [pic] B. [pic] =[pic] =[pic] C. [pic]

IV. Half Angle Identities A. [pic] B. [pic] C. [pic]

6-1 Inverse Trig Functions p. 468: 1-31 odd

I. Inverse Trig Functions A. [pic] B. [pic] C. [pic]

Find the exact value of each expression
1. [pic] 2. [pic] 3. [pic]

4. [pic] 5. [pic] 6. [pic]

Use a calculator to find each value.
7. [pic] 8. [pic] 9. [pic]

Find the exact value of each expression.
10. [pic] 11. [pic] 12. [pic]

6-2 Inverse Trig Functions Continued p. 474:1-41 odd

I. Inverse Trig Functions A. [pic] B. [pic] C. [pic]

Find the exact value of each expression.
1. [pic] 2. [pic] 3. [pic]

4. [pic] 5. [pic] 6. [pic] 7. [pic]

Find the exact value of each.
8. [pic] 9. [pic] 10. [pic]

Use a calculator to find each value.
11. [pic] 12. [pic]

Trigonometric Identities Trig Identities Worksheet: 1-6 all, 9, 13, 15, 19

I. Reciprocal Identities [pic]

II. Quotient Identities [pic]

III. Pythagorean Identities [pic]

Simplify each expression.
1. [pic] 2. [pic] 3. [pic]

4. [pic] 5. [pic] 6. [pic]

7. [pic]

6-3 Trig Identities p. 480: 1-29 odd, omit 3

I. Guidelines for Verifying Trig Identities A. Begin with the most complicated side B. Work on one side only C. Rewrite sums or differences of quotients as one single quotient D. Rewrite in terms of sine and cosine only E. Factor ( GCF or Difference of

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    EXAMPLE: Use the Table below to find the six trigonometric functions of each given real number t. π π (a) t = (b) t = 3 2 Solution: (a) From the Table, we see that the terminal point determined by √ t = √ is P (1/2, 3/2). Since the coordinates are x = 1/2 and π/3 y = 3/2, we have √ √ π 3 3/2 √ π 1 π sin = cos = tan = = 3 3 2 3 2 3 1/2 √ √ π 3 2 3 π π 1/2 csc = = sec = 2 cot = √ 3 3 3 3 3 3/2 (b) The terminal point determined by π/2 is P (0, 1). So π π 1 π 0 π cos = 0 csc = = 1 cot = = 0 sin = 1 2 2 2 1 2 1 But tan π/2 and sec π/2 are undefined because x = 0 appears in the denominator in each of their definitions. π . 4 Solution: √ From the Table above, we see that √ terminal point determined by t = π/4 is the √ √ P ( 2/2, 2/2). Since the coordinates are x = 2/2 and y = 2/2, we have √ √ √ π 2 2 2/2 π π sin = =1 cos = tan = √ 4 2 4 2 4 2/2 √ π √ π π √ 2/2 csc = 2 sec = 2 cot = √ =1 4 4 4 2/2 EXAMPLE: Find the six trigonometric functions of each given real number t =…

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