Two Variable Inequalities Research Paper
Two Variable Inequalities
Ashford University
MAT222
Two Variable Inequalities
In this week’s assignment, we examine two-variable inequalities. This includes independent variables, dependent variables and graphic solutions of these inequalities although graphs can express many different possibilities of answers. In this week’s assignment, number 68 on page 539 in our text Elementary and Intermediate Algebra (Dugopolski, 2012) is our given problem. The graph below is similar to the one in our text. It shows all of the possibilities of refrigerators and TVs that will fit into an 18-wheeler. A shipping container can carry maximum of 110 refrigerators and no TV’s, or maximum of no TV’s and 330 refrigerators. We need to write an equation …show more content…
Will the truck hold 51 refrigerators and 176 TVs?
This is another test point and will be worked the same way. x + y ≤ 330 Linear inequality. x(51) + y(176) ≤ 330 Points are plugged in and multiply.
51+ 176 ≤ 330 Add.
227 ≤ 330 This is correct. So the truck could also hold the amount given. The following problem will require me to find a minimum and maximum range. I will use the inequality found in the first part of problem 68 to solve the two following scenarios:
The Burbank Buy More store is going to make an order which will include, at most, 60 refrigerators. What is the maximum number of TVs that could also be delivered on the same 18-wheeler? x + y ≤ 330 Linear inequality. x(60) + y ≤ 330 Here I will plug in 60 into the linear inequality and multiply.
60 + y ≤ 330 Subtract 60 from both sides. y ≤ 270 Final solution.
The maximum number of TV’s that could also be delivered on the same truck would be 270. The graph would now have a horizontal line at y = 270 and a vertical line at x = 60, and the rectangular shape would be shaded. The only possible shipment amounts would fall inside that rectangle. T
E
E-400 ( (0,
Ashford University
MAT222
Two Variable Inequalities
In this week’s assignment, we examine two-variable inequalities. This includes independent variables, dependent variables and graphic solutions of these inequalities although graphs can express many different possibilities of answers. In this week’s assignment, number 68 on page 539 in our text Elementary and Intermediate Algebra (Dugopolski, 2012) is our given problem. The graph below is similar to the one in our text. It shows all of the possibilities of refrigerators and TVs that will fit into an 18-wheeler. A shipping container can carry maximum of 110 refrigerators and no TV’s, or maximum of no TV’s and 330 refrigerators. We need to write an equation …show more content…
Will the truck hold 51 refrigerators and 176 TVs?
This is another test point and will be worked the same way. x + y ≤ 330 Linear inequality. x(51) + y(176) ≤ 330 Points are plugged in and multiply.
51+ 176 ≤ 330 Add.
227 ≤ 330 This is correct. So the truck could also hold the amount given. The following problem will require me to find a minimum and maximum range. I will use the inequality found in the first part of problem 68 to solve the two following scenarios:
The Burbank Buy More store is going to make an order which will include, at most, 60 refrigerators. What is the maximum number of TVs that could also be delivered on the same 18-wheeler? x + y ≤ 330 Linear inequality. x(60) + y ≤ 330 Here I will plug in 60 into the linear inequality and multiply.
60 + y ≤ 330 Subtract 60 from both sides. y ≤ 270 Final solution.
The maximum number of TV’s that could also be delivered on the same truck would be 270. The graph would now have a horizontal line at y = 270 and a vertical line at x = 60, and the rectangular shape would be shaded. The only possible shipment amounts would fall inside that rectangle. T
E
E-400 ( (0,