Suppose a ball is thrown into the sky at a velocity of 64ft/sec from an initial height of 100ft. We would set the quadratic equation as (s)0=-gt^2+v0t+h0 and substitue values for gravity, velocity, and initial height to equal 0=-16t^2+64t+100. If we want to find out after how many seconds the ball will land, we can leave the equation set to zero and solve for t, using the quadratic formula. This will give us a solutions for t = SQRT(41)/2 (approximately 3.2 seconds) or t = -SQRT(41)/2 (approximately -3.2 seconds). Because we are only interested in positive values and negative values would not make any sense in this application, the ball will land after 3.2 seconds have passed, meaning that t = +3.2 seconds when the postion is at 0 or ground level; Position (3.2,0) on the…
This experiment was to use kinetics of projectile motion and free falling bodies to determine the distance a ball will travel after it hits a bounce plate. To determine this we had to use the equations x=(1/2)at2 and v=v0+at and derive an equation that will determine the distance the ball will travel based on the height of the bounce plate and the height of where the ball will be dropped above the bounce plate. The equation made was g*(sqrt(2)/sqrt(g))*(sqrt(H)*sqrt(h)). From here we can make an estimate of how far the ball will travel after it hits the bounce plate.…
the ball is modeled by the graph below where t = time in seconds and h = height…
The height in metres of a ball dropped from the top of the CN Tower is given by h(t)= -4.9t2+450, where t is time elapsed in seconds.…
From the Figure 7, there is a negative relationship between the loft angle of golf club and the linear velocity of golf ball. Which means as the loft angle increases, the linear velocity of ball decreases. The golf ball travels with relatively fast velocity at 9.2ms-1, when the loft angle is 0 degree, but it travels relatively slower at 3.7ms-1 when the loft angle is 80 degree. Also, the shape of graph seems to be a non linear graph rather than linear graph, because a linear best fit line does not pass through the error bars exactly.…
| The height h in feet of an object after t seconds is given by the function…
A ball is thrown upward at time t = 0 s from the ground with an initial velocity of 4 m/s (~ 9 mph). Assume that g = 10 m/s2.…
Drop the ball and determine the total bounce height of the ball, which would be the distance from the surface to the bottom of the ball at the top of its bounce.…
EXAMPLE 5: A ball is thrown vertically upward from a window that is 3.6 m above the ground. The ball's initial speed is 2.8 m/s and the acceleration due to gravity is 9.8 m/s2.…
Are You Ready For Some Football? The height of a punted football can be modeled with the quadratic function: h = -9.8t2 + 25t + 0.6 where t is the time since the ball was kicked and h is the height of the ball in meters.…
Step 3: First taking the smallest ball and dropping it from the 4 foot point. Then make a tick mark on the paper where the ball hits the highest.…
What dimension controls time in falling body and projectile motion problems? - The vertical dimension.…
The purpose of this experiment was to find the effect of the distance ran before kicking a soccer ball on the distance the ball travels. The data collected shows that as the distance ran before kicking the ball increased, the distance the ball traveled increased. In other words, the farther back the person started running towards the ball, the farther they were able to kick it. When starting at 0 meters, the person had an awkward kick because they weren’t able to get a running start, making the ball not go very far. However, as soon as they were able to start further away from the ball, at 1 meter, the ball went a lot farther because they had more momentum going into the ball. The hypothesis was if the distance before kicking a ball is increased,…
every step he takes, then he is airborne for ⅛ of a second. And if his horizontal speed is 3600…
Make sure that when the streamlined bob is suspended from the magnet that its oscillations have stopped before releasing it. Do not tighten the knob that holds the photogates in place too tightly.…