Week 7 Homework

Week 7 MA 3110 11/5/2012
Pg. 485
Q: 8
Number in group 129 805 n's
Number experiencing insomnia 19 13 x's a= 0.05 (a) p-bar= (x1+x2)/(n1 + n2) 0.034261242 n1 = 129 (b) z= (p-hat diff)/sqrt(p-bar*q-bar*(1/n1+1/n2)) 7.601787316 n2 = 805 q-hat's (c) za/2 = ± 1.96 p1-hat= 0.147286822 0.852713178 (d) P-value= 2.93099E-14 p2-hat= 0.016149068 0.983850932 Q: 10
(a) E= 0.06177357 OR using the table value
(b) 0.069364183 µ2 claim n1 = 25 t= (x-bar diff)/sqrt(s1^2/n1+s2^2/n2) 8.074687922 n2 = 25 P-value= 1.33814E-08 x1-bar= 21.1 x2-bar= 13.2 s1= 3.2 s2= 3.7 "Reject Ho; there is sufficient evidence to conclude that μ1 – μ2 > 0. There is sufficient evidence to support the claim that unfiltered king size cigarettes have a mean tar content greater than that of filtered 100 mm cigarettes. The results suggest that filters are effective in reducing the tar content in cigarettes.
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Pg. 500
Q: 19
H0: m1 = m2
H1: m1 ≠ m2 a= 0.05 ta/2= 2.063898562 n1 = 25 t = -0.721387321 ABS= 0.721 n2 = 25 P-value = 0.477874634 x1-bar= 0.87 x2-bar= 0.92 s1= 0.24 s2= 0.25 Do not reject Ho; there is not sufficient evidence to conclude that μ₁–μ₂≠0. There is not sufficient evidence to support the claim that menthol cigarettes and non-menthol cigarettes have different amounts of nicotine. No; menthol does not appear to have an effect on the nicotine content.

Pg. 512
Q: 12
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