What Is Sodium Hypochlorite (Naocl) In Acetic Acid
PurposeIn this experiment, sodium hypochlorite (NaOCl) in acetic acid mixture was used to oxidize emdo-borneol (an alcohol) to camphor (a ketone). The product would then be purified by sublimation and then be analyzed by Infrared spectroscopy and melting point test.
Procedure and ObservationsPlease refer to the lab manual and the carbon copy attached.
Data and CalculationsWeight of endo-borneol = 0.2013gNo of moles of endo-borneol = 0.2013g/154.25g mol-1 = 1. 305mmolSince one mole of endo-borneol should give one mole of camphorTheoretical yield of camphor = (1.305 mmol )( 152.23g mol-1) = 0. 1987gTheoretical melting point of camphor = 179.75 oCActual Yield of the product (camphor) = 9. 5360 - 9. 4873 = 0. 0487 g% Yield of the product = (100)* …show more content…
In acidic solution, iodide ions should be oxidized by the hypochlorite ions to iodine and therefore gave a purple black color.
The result of this experiment was not very satisfactory, although the reaction was carefully controlled so that the temperature was kept more or less at 40oC. First of all, the yield of the product (24.5%) was quite low. This was mainly because of the fact that there was significant loss of materials during transfer of crystals and because of incomplete conversion of endo-borneol to camphor. It was observed that during swirling of endo-borneol to help it dissolve in acetic acid, some of them got stuck on the wall of the flask, and therefore was not being oxidized by the hypochlorite.
For improvement, it might be a good idea not to add all the acetic acid at one time, but left a little bit of it to wash down the endo-borneol stuck at the wall. The loss of crystals during transfer could be minimized by more careful handling. However, some loss seemed to be inevitable as it was impossible to get all the tiny crystals out from one flask to
Procedure and ObservationsPlease refer to the lab manual and the carbon copy attached.
Data and CalculationsWeight of endo-borneol = 0.2013gNo of moles of endo-borneol = 0.2013g/154.25g mol-1 = 1. 305mmolSince one mole of endo-borneol should give one mole of camphorTheoretical yield of camphor = (1.305 mmol )( 152.23g mol-1) = 0. 1987gTheoretical melting point of camphor = 179.75 oCActual Yield of the product (camphor) = 9. 5360 - 9. 4873 = 0. 0487 g% Yield of the product = (100)* …show more content…
In acidic solution, iodide ions should be oxidized by the hypochlorite ions to iodine and therefore gave a purple black color.
The result of this experiment was not very satisfactory, although the reaction was carefully controlled so that the temperature was kept more or less at 40oC. First of all, the yield of the product (24.5%) was quite low. This was mainly because of the fact that there was significant loss of materials during transfer of crystals and because of incomplete conversion of endo-borneol to camphor. It was observed that during swirling of endo-borneol to help it dissolve in acetic acid, some of them got stuck on the wall of the flask, and therefore was not being oxidized by the hypochlorite.
For improvement, it might be a good idea not to add all the acetic acid at one time, but left a little bit of it to wash down the endo-borneol stuck at the wall. The loss of crystals during transfer could be minimized by more careful handling. However, some loss seemed to be inevitable as it was impossible to get all the tiny crystals out from one flask to