What Is The Amino Acid Sequence Produced By Translation Of The Dna Sequence?
Consider the following double-stranded DNA sequence:
5’-CAG AAG AAA ATT AAC ATG TAA-3’
3’-GTC TTC TTT TAA TTG TAC ATT-5’
If the bottom strand serves as the template, what is the mRNA sequence produced by transcription of this DNA sequence and Why?
5’-CAG AAG AAA AUU AAC AUG UAA-3’ mRNA sequence
3’-GTC TTC TTT TAA TTG TAC ATT-5’ DNA template strand
We get the mRNA sequence due the transcription process, which gives us the RNA bases that are complementary to the DNA template strand that uses uracil opposite to adenine. The RNA polymerase which is an enzyme that moves from the 3’ to 5’end on DNA template strand to synthesis mRNA from 5’ to 3’.
b. What is the amino acid sequence produced by translation of the mRNA sequence? …show more content…
We will suppose that Aa is one pair of the homologous chromosome and Bb is the second pair. By using where n is the number of chromosome (2 because haploid) we expect to have 4 different combination which are (aB, Ab, aB, ab) as illustrated in figure 1.
Mr. and Mrs. Smith are carriers for Cystic Fibrosis genetic disorder.
State what percentage of their offspring will be affected, carrier and unaffected.
Describe which molecular diagnostic technique can be used to identify whether their newborn infant daughter is affected by Cystic fibrosis genetic mutation and how.
While performing PCR assuming there was only one target sequence of DNA present in your sample and the reaction was 100% efficient, how many copies would be present after:
20 cycles? 20 cycles will give 220 DNA copies.
25 cycles? 25 cycles will give 225 DNA copies.
30 cycles? 30 cycles will give 230 DNA copies.
A Drosophila male carrying a recessive X-linked mutation for yellow body is mated to a homozygous wild-type female with gray body. The daughters of this mating all have uniformly gray bodies. Why aren’t their bodies a mosaic of yellow and gray …show more content…
In DNA Microarray technique define what is a probe and a sample? While performing Microarray analysis for mRNA sample state why rRNA and tRNA should be removed during sample preparation.
Cells isolated from a dissected specimen of small tumor discovered in a 55-year old woman is send to molecular genetics laboratory for p53 mutation analysis. DNA isolated from the tumor cells was screened for sequence alterations due to difference in the nucleotide sequence caused by mutations in the exon 4 to 9 of p53 gene. The results of polyacrylamide gel electrophoresis and subsequent direct sequencing for exon 5 are shown below:
What information is gained from PAGE results?
What additional information is gained from sequencing in regards to the patient condition?
References
Lewis, R. (2012). Human Genetics: Concepts and Applications (10th ed.). New York: McGraw-Hill.
The Polymerase Chain Reaction (n.d.). Retrieved from http://faculty.plattsburgh.edu/donald.slish/pcr.html
Tortora, G. J., Funke, B. R., & Case, C. L., et al. (2016). Microbiology: An Introduction (12th ed.). Essex: Pearson Education
5’-CAG AAG AAA ATT AAC ATG TAA-3’
3’-GTC TTC TTT TAA TTG TAC ATT-5’
If the bottom strand serves as the template, what is the mRNA sequence produced by transcription of this DNA sequence and Why?
5’-CAG AAG AAA AUU AAC AUG UAA-3’ mRNA sequence
3’-GTC TTC TTT TAA TTG TAC ATT-5’ DNA template strand
We get the mRNA sequence due the transcription process, which gives us the RNA bases that are complementary to the DNA template strand that uses uracil opposite to adenine. The RNA polymerase which is an enzyme that moves from the 3’ to 5’end on DNA template strand to synthesis mRNA from 5’ to 3’.
b. What is the amino acid sequence produced by translation of the mRNA sequence? …show more content…
We will suppose that Aa is one pair of the homologous chromosome and Bb is the second pair. By using where n is the number of chromosome (2 because haploid) we expect to have 4 different combination which are (aB, Ab, aB, ab) as illustrated in figure 1.
Mr. and Mrs. Smith are carriers for Cystic Fibrosis genetic disorder.
State what percentage of their offspring will be affected, carrier and unaffected.
Describe which molecular diagnostic technique can be used to identify whether their newborn infant daughter is affected by Cystic fibrosis genetic mutation and how.
While performing PCR assuming there was only one target sequence of DNA present in your sample and the reaction was 100% efficient, how many copies would be present after:
20 cycles? 20 cycles will give 220 DNA copies.
25 cycles? 25 cycles will give 225 DNA copies.
30 cycles? 30 cycles will give 230 DNA copies.
A Drosophila male carrying a recessive X-linked mutation for yellow body is mated to a homozygous wild-type female with gray body. The daughters of this mating all have uniformly gray bodies. Why aren’t their bodies a mosaic of yellow and gray …show more content…
In DNA Microarray technique define what is a probe and a sample? While performing Microarray analysis for mRNA sample state why rRNA and tRNA should be removed during sample preparation.
Cells isolated from a dissected specimen of small tumor discovered in a 55-year old woman is send to molecular genetics laboratory for p53 mutation analysis. DNA isolated from the tumor cells was screened for sequence alterations due to difference in the nucleotide sequence caused by mutations in the exon 4 to 9 of p53 gene. The results of polyacrylamide gel electrophoresis and subsequent direct sequencing for exon 5 are shown below:
What information is gained from PAGE results?
What additional information is gained from sequencing in regards to the patient condition?
References
Lewis, R. (2012). Human Genetics: Concepts and Applications (10th ed.). New York: McGraw-Hill.
The Polymerase Chain Reaction (n.d.). Retrieved from http://faculty.plattsburgh.edu/donald.slish/pcr.html
Tortora, G. J., Funke, B. R., & Case, C. L., et al. (2016). Microbiology: An Introduction (12th ed.). Essex: Pearson Education