White Seedling Experiment

For this experiment you will need green and white seedling The purpose of this experiment was to test two different hypotheses about the credibility of Mendel’s law of independent assortment and law of segregation. First is that the first plant is the product of a monohybrid cross. A monohybrid cross is “a cross between two organisms that are heterozygous for the character being followed” (Urry, G-21). The monohybrid is represented through a phenotypic ratio of 3:1 and a dihybrid cross is represented through a phenotypic ratio of 9:3:3:1 (Mark Lavery). The second hypothesis was that the second set of corn was based on a dihybrid cross. A dihybrid cross is “a cross between two organisms that are organisms that are each heterozygous for both
There were 230 purple smooths, 93 purple wrinkled, 95 yellow, smooths, and 76 yellow, wrinkled. To find the chi-square the equation for the purple smooth was done first. The observed value of the purple smooth, 230 had the expected value 277.875 subtracted from it, when that value was found, it was squared, when the top value was found, it was then divided by the expected value 277.875. The equation looked like this (230-277.875) ^2/277.875 = 2292/277.875 = 8.25. Next the purple wrinkled was plugged into the equation. The observed value of the purple wrinkled, 93 had the expected value 92.625 subtracted from it, when that value was found, it was squared, when the top value was found, it was then divided by the expected value 92.625. The equation looked like this (93-92.625) ^2/92.626 = .14/92.625=.0015. Next the yellow, smooth was plugged into the equation. The observed value of the yellow, smooths, 95 had the expected value 92.625 subtracted from it, when that value was found it was squared, when the top value was found it was then divided by the expected value 92.625. The equation looked like this, (95-92.625) ^2/92.626 = 5.64/92.625=.061. Lastly, the yellow, wrinkled was plugged into the equation. The observed value of the yellow, wrinkled, 76 had the expected value 30.875 subtracted from it, when that value was found, it was squared, when the top value was found, it was then divided by the expected value 30.875. The equation looked like this (76-30.875) ^2 =2036.27/30.875= 65.95. After finding all these values they are added together to find the chi-square, the sum of these four numbers is 74.2625. The chi-square for the corn genetics shows that there is a significant deviation between the expected values. This means that the outcome is nowhere close to the expected ratio for the corn genetics