Why Do You Think Someone Offers To Give You A Million Dollars
#6:Treasure Chest
Problem: Someone offers to give you a million dollars($1,000,000) in one-dollar ($1) bills. To receive the money, you must lie down; the million one-dollar bills will be placed on your stomach.
If you keep them on your stomach for 10 minutes, the money is yours! Do you accept the offer?
Solution: Each dollar bill weighs 1 gram, if we multiply 1gram by 1,000,000 dollars we get a weight of 1,000,000 grams. If there are 454 grams in a pound then $1,000,000 will equal 2202 pounds, 2 ounces, and 29grams.
1gm x 1,000,000 =1,000,000gm
1,000,000gm/454 = 2202.64 = 2202 pounds
64gm/28=2.29 = 2ounces and 29 grams
So 1,000,000 one dollar bills will weigh 2202 pounds, 2 ounces, and 29grams
This much weight would most definitely …show more content…
The sum of all those numbers is 6. What is the next number that has the property of equaling the sum of all the natural numbers?
Solution: The next number that has the property of equaling the sum of all the natural numbers that divide evenly into it is 28. The numbers 1,2,4,7,14 all divide equally onto 28. The sum of all those numbers equals 28 (1+2+4+7+14). So, 28 is the next perfect number after 6.
#15: The Last One:
Problem:Play the game using any natural numbers. If the number is even, divide it by 2. If the number is odd, triple it and then add 1. Repeat the process until you win by reaching 1. Complete the task 4 times using numbers 19,11,22, and 30.
Solution: Start with number 19. Its odd so we must triple it an add 1 (19x3+1=58). We then have the number 58 which is even so we divide it by 2 (58/2=29). Then we have 28 which is even so we divide by 2 (28/2=14). Also an even number so it will be divide by 2 (14/2=7). Then we get a odd number so we will multiply by 3 and add 1 (7x3+1=22). 22 is even so divide by 2 (22/2=11). 11 is odd so multiply by 3 and add 1 (11x3+1=34). Next we divide 34 by 2 (34/2=17). 17 will need to be multiplied by 3 and added to 1 (17x3+1=52). Dived 52 by 2 (52/2=26). Divide 26 by 2 (26/2=13). 13 is odd so it must be multiplied by 3 and then add 1 (13x3+1=40). Divide 40 by 2 (40/2=20). Divide by 2 (20/2=10). Divide by 2 (10/2=5). …show more content…
#17: See the three III
Problem: What proportion of the first 10,000 natural numbers contain a 3.
Solution: So in 1-100 the numbers 3,13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93 all contain a 3 in them. So there are 19 numbers that contain a 3 in them in the numbers 1-100. Each group of hundreds contain 19 number threes (1-100, 200-299, 400-499, 500-599, 600-699, 700-799, 800-899, 900-999) in them except for 300-399 those have 100 numbers containing a 3.
So we have 19x9+100=171+100=271 threes in each thousand numbers.
So there are 271 numbers that contain a 3 in them in the numbers 1-1000. Each group of thousands also contain 271 number threes (1000-1999, 2000-2999, 4000-4999, 5000-5999, 6000-6999, 7000-7999, 8000-8999, 9000-9999) in them except for 3000-3999 those have 1000 numbers containing a 3.
So we have 271x9+1000= 2439+1000=3439
So in conclusion we have 3,439/10,000 or .3439 numbers that contain threes in them in the numbers
Problem: Someone offers to give you a million dollars($1,000,000) in one-dollar ($1) bills. To receive the money, you must lie down; the million one-dollar bills will be placed on your stomach.
If you keep them on your stomach for 10 minutes, the money is yours! Do you accept the offer?
Solution: Each dollar bill weighs 1 gram, if we multiply 1gram by 1,000,000 dollars we get a weight of 1,000,000 grams. If there are 454 grams in a pound then $1,000,000 will equal 2202 pounds, 2 ounces, and 29grams.
1gm x 1,000,000 =1,000,000gm
1,000,000gm/454 = 2202.64 = 2202 pounds
64gm/28=2.29 = 2ounces and 29 grams
So 1,000,000 one dollar bills will weigh 2202 pounds, 2 ounces, and 29grams
This much weight would most definitely …show more content…
The sum of all those numbers is 6. What is the next number that has the property of equaling the sum of all the natural numbers?
Solution: The next number that has the property of equaling the sum of all the natural numbers that divide evenly into it is 28. The numbers 1,2,4,7,14 all divide equally onto 28. The sum of all those numbers equals 28 (1+2+4+7+14). So, 28 is the next perfect number after 6.
#15: The Last One:
Problem:Play the game using any natural numbers. If the number is even, divide it by 2. If the number is odd, triple it and then add 1. Repeat the process until you win by reaching 1. Complete the task 4 times using numbers 19,11,22, and 30.
Solution: Start with number 19. Its odd so we must triple it an add 1 (19x3+1=58). We then have the number 58 which is even so we divide it by 2 (58/2=29). Then we have 28 which is even so we divide by 2 (28/2=14). Also an even number so it will be divide by 2 (14/2=7). Then we get a odd number so we will multiply by 3 and add 1 (7x3+1=22). 22 is even so divide by 2 (22/2=11). 11 is odd so multiply by 3 and add 1 (11x3+1=34). Next we divide 34 by 2 (34/2=17). 17 will need to be multiplied by 3 and added to 1 (17x3+1=52). Dived 52 by 2 (52/2=26). Divide 26 by 2 (26/2=13). 13 is odd so it must be multiplied by 3 and then add 1 (13x3+1=40). Divide 40 by 2 (40/2=20). Divide by 2 (20/2=10). Divide by 2 (10/2=5). …show more content…
#17: See the three III
Problem: What proportion of the first 10,000 natural numbers contain a 3.
Solution: So in 1-100 the numbers 3,13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93 all contain a 3 in them. So there are 19 numbers that contain a 3 in them in the numbers 1-100. Each group of hundreds contain 19 number threes (1-100, 200-299, 400-499, 500-599, 600-699, 700-799, 800-899, 900-999) in them except for 300-399 those have 100 numbers containing a 3.
So we have 19x9+100=171+100=271 threes in each thousand numbers.
So there are 271 numbers that contain a 3 in them in the numbers 1-1000. Each group of thousands also contain 271 number threes (1000-1999, 2000-2999, 4000-4999, 5000-5999, 6000-6999, 7000-7999, 8000-8999, 9000-9999) in them except for 3000-3999 those have 1000 numbers containing a 3.
So we have 271x9+1000= 2439+1000=3439
So in conclusion we have 3,439/10,000 or .3439 numbers that contain threes in them in the numbers