Yield Lab
Abstract: All the materials were measured and weighed. It was found in the experiment that the yield of copper hydroxide in 40%.
Introduction: The copper (II) sulphate is then placed in 100 mL of distilled water. Then 20 mL of CuSO4 is measured and placed 100 mL of distilled water. This can later be weighed to determine the mol of CuSO4 and the mol/L concentration. Then this was used to find out how many mL of 0.5 NaOH solution is needed to react completely with all the copper (II) sulphate in solution. Then titrate ¼ of the estimated amount number of mL of NaOH needed to react with the sulphate solution. Then add 5 mL at a time NaOH until Cu(OH)2 precipitate does not form. Record the correct number off mL which forms to NaOH solution. Fold the filter paper and stick inside the funnel, and pour the solution of copper (II) hydroxide through the filter. The purpose of this experiment is to determine the yield of copper (II) sulphate reaction.
Reagent preparation:
0.5 mol/L = mol/0.1L
0.5 (0.1L)=mol mol = 0.05
0.05 x 40 (molar mass)= 2
There are 2 grams of solid sodium hydroxide.
Method:
Weigh 100 mL beaker
Transfer anhydrous copper (II) sulphate to that beaker
Heat beaker at level 6 for 3 minutes, stirring occasionally
Removing beaker from balance and weigh after cooling for 3 minutes
Turn off heater (or leave for next group)
Measure 100 mL of distilled water into a graduated cylinder and place in 100 mL beaker with the copper (II) sulphate
Heat and mix until solid material is all gone
Let cool for 5 minutes
Measure 20 mL of CuSO4 into 200 mL beaker, and add 100 mL of water
Calculated mol of CuSO in solution and the mol/L concentration
Predict how many mL of 0.5 NaOH solution is needed to react completely with all the copper(II) sulphate in solution
Place 200 mL beaker under the titrating burnette
Record the number of mL in the burnette
Titrate quickly ¼ of the estimated number of mL of NaOH needed to
Introduction: The copper (II) sulphate is then placed in 100 mL of distilled water. Then 20 mL of CuSO4 is measured and placed 100 mL of distilled water. This can later be weighed to determine the mol of CuSO4 and the mol/L concentration. Then this was used to find out how many mL of 0.5 NaOH solution is needed to react completely with all the copper (II) sulphate in solution. Then titrate ¼ of the estimated amount number of mL of NaOH needed to react with the sulphate solution. Then add 5 mL at a time NaOH until Cu(OH)2 precipitate does not form. Record the correct number off mL which forms to NaOH solution. Fold the filter paper and stick inside the funnel, and pour the solution of copper (II) hydroxide through the filter. The purpose of this experiment is to determine the yield of copper (II) sulphate reaction.
Reagent preparation:
0.5 mol/L = mol/0.1L
0.5 (0.1L)=mol mol = 0.05
0.05 x 40 (molar mass)= 2
There are 2 grams of solid sodium hydroxide.
Method:
Weigh 100 mL beaker
Transfer anhydrous copper (II) sulphate to that beaker
Heat beaker at level 6 for 3 minutes, stirring occasionally
Removing beaker from balance and weigh after cooling for 3 minutes
Turn off heater (or leave for next group)
Measure 100 mL of distilled water into a graduated cylinder and place in 100 mL beaker with the copper (II) sulphate
Heat and mix until solid material is all gone
Let cool for 5 minutes
Measure 20 mL of CuSO4 into 200 mL beaker, and add 100 mL of water
Calculated mol of CuSO in solution and the mol/L concentration
Predict how many mL of 0.5 NaOH solution is needed to react completely with all the copper(II) sulphate in solution
Place 200 mL beaker under the titrating burnette
Record the number of mL in the burnette
Titrate quickly ¼ of the estimated number of mL of NaOH needed to