Number of seats per passenger train car 90
Average load factor (percentage of seats filled) 70%
Average full passenger fare $160
|Average variable cost per passenger $70
|Fixed operating cost per month $3,150,000
1. What is the break-even point in passengers and revenues per month?
Unit CM = $160 – $70= $90
a.) Unit of Sales = 3,150,000 / $90= 35,000 passengers
b.) Unit of Sales = 35,000 x $160= $5,600,000 revenue
2. What is the break-even point in number of passenger train cars per month?
Unit of Sales = 35,000/63= 555.5= 556 passenger cars (rounded)
3. If Springfield Express raises its average passenger fare to $ 190, it is estimated that the average load factor will decrease to 60 percent. What will be the monthly break-even point in number of passenger cars?
90 x .60 = 54
Unit CM = $190 – $70= $120
Unit of Sales = $3,150,000 / $120= 26,250 passengers
Unit of Sales = 26,250/54= 486.1
=486 passenger cars (rounded)
4. (Refer to original data.) Fuel cost is a significant variable cost to any railway. If crude oil increases by $ 20 per barrel, it is estimated that variable cost per passenger will rise to $ 90. What will be the new break-even point in passengers and in number of passenger train cars?
Unit CM = 160 – 90= 70
a.) Unit of Sales = 3,150,000 / 70 = 45,000 Passengers
b.) Unit of Sales = 45,000/63= 714.2= 714 passenger cars (rounded)
5. Springfield Express has experienced an increase in variable cost per passenger to $ 85 and an increase in total fixed cost to $ 3,600,000. The company has decided to raise the average fare to $ 205. If the tax rate is 30 percent, how many passengers per month are needed to generate an after-tax profit of $ 750,000?
Unit CM = 205 – 85= 120 after-tax profit = 750,000/(1-.30)= 750,000/.70= 1071428.57
205X – 3,600,000 – 85X = 1,071,428.57
+ 3,600,000 = +